How can I separate some repeated patterns in a row into multiple rows using bash script?

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I have some problem with bash script.

I've got a string which has some repeated patterns like this.

1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4 ...

Each fields is separated by tab key.

I want it to look like this...

1 2 3 4
1 2 3 4
1 2 3 4
...

How can I solve this problem using bash script like cut, sed, awk ... ?

It looks very easy but so difficult to me...

Posted 12-Oct-13 16:58pm

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101zeeshan101 · Answer 1 · 2013-10-14T07:45:00

You can use sed like this:

Solution:
s='1 2 3 4 1 2 3 4 1 2 3 4 1 2 3 4'
p='1 2 3 4'
echo "$s"|sed "s/$p\s*/&\n/g"
1 2 3 4
1 2 3 4
1 2 3 4
1 2 3 4

You can use infinite while loop and use the input file and iterate through each line to use this logic for murtiple lines.

Live Demo
http://ideone.com/P59OCJ[^]