order by date in varchar

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i have date in varchar format(16/01/2014)..
and i have to order by my data in date format...

when i am using simple order by date..its order by works only in month and date not with year..eg

10/12/2013
31/11/2013
01/01/2014

my query provide this result..how to manage this data with year bases also..like
01/01/2014
10/12/2013
31/11/2013

Posted 16-Jan-14 6:09am

Rajivdablu

Updated 16-Jan-14 6:10am

v2

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Richard MacCutchan 16-Jan-14 13:00pm

Unfortunately you are doing this wrong. You should use the Date or DateTime type to store dates in a database, not strings.

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CPallini · Answer 1 · 2014-01-16T07:00:00

Solution 1

Convert the varchars to dates (see, for instance "mySQL convert varchar to date" at Stack Overflow[^]) before ordering.

Posted 16-Jan-14 7:00am

CPallini

Comments

Maciej Los 16-Jan-14 15:20pm

+5!

CPallini 16-Jan-14 15:27pm

Thank you. However, have a look at skydger's solutions (3 different ones!).

skydger · Answer 2 · 2014-01-16T07:27:00

There are several way to achieve your goal
1. Convert your string to date[time]

SQL

SELECT `date_column`
  FROM `your_table`
 ORDER BY str_to_date(`date_column`, '%d/%m/%Y') DESC

2. Reformat your date string to yyyy-mm-dd (or yyyy/mm/dd etc)

SQL

SELECT `date_column`
  FROM `your_table`
  ... 
 ORDER BY CONCAT_WS('-', SUBSTRING(`date_column`, 7, 4), SUBSTRING(`date_column`, 4, 2), SUBSTRING(`date_column`, 1, 2)) DESC

3. Order by years, months and days separately

SQL

SELECT `date_column`
  FROM `your_table`
  ... 
 ORDER BY CAST(SUBSTRING(`date_column`, 7, 4) AS INT), CAST(SUBSTRING(`date_column`, 4, 2) AS INT), CAST(SUBSTRING(`date_column`, 1, 2)) AS INT) DESC