Round function in vb 6.0

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VB6

Hi
In VB6.0,

Round(1.35,1) gives 1.4

but i need 1.3

Thanks in advance....

Posted 21-Jan-14 21:45pm

ThangamSundar

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CPallini · Answer 1 · 2014-01-21T21:52:00

Solution 1

You could use Fix for the purpose, e.g.

VB

Dim a as Double
Dim b as Double
a = 1.35
b = Fix(a * 10)/10

Posted 21-Jan-14 21:52pm

CPallini

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ThangamSundar 22-Jan-14 4:09am

its working....
but a=1.2 means its gives 1.1...
but need 1.2

CPallini 22-Jan-14 4:28am

This is due to intrinsic inaccuracy of internal representation of Double numbers, that is, you write 1.2 in your application but it is actually stored like 1.19999999999...