Differences between string s= new string (); and string s=“abv”;

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Please Let Me Know The differences Between These Two Object Creation.. In the First Case object will be created in Heap Area But In second Case Object Will Be created in String Constant Pool (scp) Area ..Is It The Answer or something else.

Posted 25-Feb-14 19:30pm

RAVI _4378

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Sergey Alexandrovich Kryukov 26-Feb-14 2:35am

First case won't even compile. Was it so difficult to check it up, before asking a question? :-)
—SA

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Sergey Alexandrovich Kryukov · Accepted Answer · 2014-02-25T20:40:00

Solution 2

Not true at all. This type is designed in much wiser way: there is no such constructor. These constructors do not exist: string(); string(string); the are simply never needed and having them would be even harmful.

You mentioned the pool. It also does not work as you thought, and it is called intern pool. Please read about interning; it is very interesting:
http://en.wikipedia.org/wiki/String_intern_pool[^],
http://msdn.microsoft.com/en-us/library/system.string.intern(v=vs.110).aspx[^],
http://msdn.microsoft.com/en-us/library/system.string.isinterned(v=vs.110).aspx[^].

—SA

Posted 25-Feb-14 20:40pm

Sergey Alexandrovich Kryukov

Comments

Maciej Los 26-Feb-14 3:02am

+5

Sergey Alexandrovich Kryukov 26-Feb-14 9:35am

Thank you, Maciej.
—SA

RAVI _4378 26-Feb-14 3:17am

Plz tell me the reason why This Code will Not Compile

package mypack;

public class Test {

public static void main(String args[])
{

String s=new String ();
String s1="abc";

System.out.println(s1);
System.out.println(s);

}

}

o/p
abc

This Compiling As well As o/p

Sergey Alexandrovich Kryukov 26-Feb-14 9:37am

"String does not contain a constructor that takes 0 arguments"
—SA