Pointer operator mistaken for a arithmetic operator

Question

1.00/5 (3 votes)

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    MyLong n;
    d.setVector(this->vector);

    MyLong& e = *d;

MyLong operator*(MyLong&, MyLong&)
 MyLong operator*(MyLong &l1, MyLong &l2)
          ^

Ok, I am not sure what I am doing wrong, but I've been pulling my hair for 10 minutes.

Posted 4-Mar-14 16:05pm

OpenTheTrollGate

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Comments

Sergey Alexandrovich Kryukov 4-Mar-14 22:17pm

It cannot be the real C++ code you would write. Tell us the truth: these lines are unrelated fragments of code, right? It is not correct or incorrect code; this is not C++ code at all.
Please provide some integral self-consistent sample of C++ compilation unit. Please see: SSCCE.
In other words: close the troll gate.
—SA

[no name] 4-Mar-14 22:17pm

How about explaining the problem clearly and logically.

Sergey Alexandrovich Kryukov 4-Mar-14 22:18pm

Trolls are infiltrating through the gate; please see above... :-)
—SA

[no name] 4-Mar-14 22:40pm

Indeed.

OpenTheTrollGate 4-Mar-14 22:23pm

Sorry, I just found what the problem was. You have to initialize the pointer MyLong* pointer = &d. and then use d the way you like.

[no name] 4-Mar-14 22:36pm

There is no "MyLong *pointer" in your question so it and your solution are complete drivel - nothing more than spam.

Stefan_Lang 5-Mar-14 8:58am

I agree. Seems like this guy is willfully omitting information and not responding to requests for more, or a rephrasing of the question. He doesn't appear to have any problem with the english language either, so I conclude this user name was chosen deliberately.

For now I just downvoted the question - something I normally never do. However, if he keeps posting similar drivel, he'll earn a spam report.

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