I solved it!!!!!
using System;
using System.Collections.Generic;
using System.Collections;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.HtmlControls;
using CrystalDecisions.Web;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.WebControls;
using CrystalDecisions.CrystalReports.Engine;
using CrystalDecisions.Shared;
using CrystalDecisions.Windows.Forms;
using CrystalDecisions.ReportSource;
using System.Data;
using System.Data.SqlClient;
using System.Configuration;
using System.Xml.Linq;
using System.Web.SessionState;
using CrystalDecisions.ReportAppServer;
using System.Drawing;
using System.Drawing.Printing;
namespace SACSCOCLogin1._1
{
public partial class ReportFormA : System.Web.UI.Page
{
protected void Page_Load(object sender, EventArgs e)
{
SqlConnection con = new SqlConnection(System.Configuration.ConfigurationManager.ConnectionStrings["HotConnectionString"].ConnectionString);
con.Open();
TextBoxINST_ID.Text = Session["inst_id"].ToString();
CrystalReportViewer1.Visible = true;
ReportDocument CrystalReport = new ReportDocument();
ParameterField paramField = new ParameterField();
ParameterFields paramFields = new ParameterFields();
ParameterDiscreteValue paramDiscreteValue = new ParameterDiscreteValue();
paramField.Name = "inst_id";
paramField.CurrentValues.Clear();
paramDiscreteValue = new ParameterDiscreteValue();
paramDiscreteValue.Value = TextBoxINST_ID.Text;
paramFields.Add(paramField);
CrystalReportViewer1.ParameterFieldInfo = paramFields;
CrystalReport.Load(Server.MapPath("FormAReport.rpt"));
string sessiontype = TextBoxINST_ID.Text;
CrystalReport.SetParameterValue("inst_id", TextBoxINST_ID.Text);
string sessionid = TextBoxINST_ID.Text;
CrystalReport.SetParameterValue("inst_id", TextBoxINST_ID.Text);
CrystalReportViewer1.ReportSource = CrystalReport;
con.Close();
}
}
}
I just added the connection String and comment out the //CrystalReport.SetDatabaseLogon("Admin", "Enter", "SQL", "Hot");