How Do I Stop The Input Process When I Input Five Negative Integer Numbers?

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C#

main()
{
    int a[20],x;
    int n=a[0];

        for(x=0; x<20; x++)
         {
           cout<<"Enter integer : ";
           cin>>a[x];


           while(a[x]<0)
            {
              cout<<"Enter integer : ";
              cin>>a[x];
            }
         }

This should be the output

Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: 1
Input: -1
Input: -1
Input: -1
Input: 1
Input: -1
Input: 1
Input: -1

Stop!

Posted 25-Jul-14 23:21pm

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*Abhijit Ghosh (Subho)* · Accepted Answer · 2014-07-25T23:28:00

Solution 1

use a counter variable inside the for loop

C++

int countNegative=0
if(a[x]<0)
 countNegative++

use a break statement when the countNegative becomes 5

C++

if(countNegative==5)
 break;

Posted 25-Jul-14 23:28pm

Abhijit Ghosh (Subho)

Updated 25-Jul-14 23:36pm

v2

Comments

Safe Search 26-Jul-14 5:46am

Thank you very much sir.

Abhijit Ghosh (Subho) 26-Jul-14 5:52am

You are welcome.
Rate the answer if it solves your issue.
Abhijit

Safe Search 26-Jul-14 6:52am

Sir my another problem is when i display the input numbers it displays unwanted numbers and how can i display the input numbers properly?

Abhijit Ghosh (Subho) 26-Jul-14 6:57am

What do you mean by unwanted numbers?

Safe Search 26-Jul-14 7:10am

Like this sir...

Enter integer 0 : 1
Enter integer 1 : 1
Enter integer 2 : 1
Enter integer 3 : —1
Enter integer 4 : —1
Enter integer 5 : —1
Enter integer 6 : —1
Enter integer 7 : —1
-1
-1
-1
-1
-1
31619
293384
421 62
1200101
-1
5535
293364
4230143
1233024

The condition to terminate the input has been satisfied.

Safe Search 26-Jul-14 7:14am

here's my incorrect algorithm

for(int y=0; y<20; y++)
{
cout<<a[y]<<endl;
}
cout<<"The condition to terminate the input has been satisfied."<<endl;

Abhijit Ghosh (Subho) 26-Jul-14 7:21am

I think those are just garbage values. Have a look at your array size and see how many numbers you are storing. Maybe you are not storing anything in some of the array cells whose values you are printing.

Please post your entire code. It's very diificult to say otherwise.

Safe Search 26-Jul-14 7:24am

for(x=0; x<20; x++)
{
cout<<"Enter integer "<<x<< " : ";
cin>>a[x];

if(a[x]<0)
{
n++;
}
if(n==5)
{
break;
}
}

for(int y=0; y<20; y++)
{
cout<<a[y]<<endl;
}
cout<<"The condition to terminate the input has been satisfied."<<endl;

Abhijit Ghosh (Subho) 26-Jul-14 7:47am

Like I was saying you are printing all 20 but you have less inputs. Modify the for loop to run till x.

Safe Search 26-Jul-14 7:50am

Thank you so much! I learned a lot from you.