How Can I Pass Multiple Argument In $1 In Shell Script?

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How can i pass all argument in $1 in shell script. I mean i don't want to use other $2,$3..$9 without that how can i pass all the argument in only $1. if it's possible than someone tell me how to achieve that.

Posted 20-Aug-14 23:11pm

DilipSutariya

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ChauhanAjay 21-Aug-14 5:14am

You mean to say you don't want multiple variable for passing the arguments. If this is the case then u could concatenate all the value with a separator and pass the argument and later split it on the separator and get the individual values.

DilipSutariya 21-Aug-14 5:21am

yes i get it what you want to say but can i pass array as a argument in shell script?

ChauhanAjay 21-Aug-14 5:23am

I have just given a general solution. I am not sure about passing array as a argument in shell script. Sorry.

DilipSutariya 21-Aug-14 5:28am

Ok Thank you. @ChauhanAjay
Regards,
Dilip Sutariya

Richard MacCutchan 21-Aug-14 7:52am

Just place all the items within double quotes like: "one two three ... etc".

DilipSutariya 22-Aug-14 1:41am

Thanks. Richard MacCutchan

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