Parse error: syntax error, unexpected T_IF in /home/u506124311/public_html/ag/page.php on line 45

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Hi can anybody assist with this syntax error please. I'm trying to replace bad words with ":-x" when it is being retrieved from the database...

PHP

$bwords = aray("admin", "mod");
$pmsg = if($list['StringyChat_message'] = $bwords) {echo ":-x";} else { echo "$list['StringyChat_message']";}

Posted 28-Aug-14 14:45pm

cobusbo

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ChauhanAjay · Answer 1 · 2014-08-28T17:05:00

Solution 1

Try changing the line from

PHP

$pmsg = if($list['StringyChat_message'] = $bwords) {echo ":-x";} else { echo "$list['StringyChat_message']";}

To

PHP

$pmsg = ($list['StringyChat_message'] == $bwords) ? ":-x" : $list['StringyChat_message'];

Posted 28-Aug-14 17:05pm

ChauhanAjay

Comments

cobusbo 29-Aug-14 5:54am

Ok I changed it to

$bwords = aray('ass', 'elo' );
$pmsg = ($list['StringyChat_message'] == $bwords) ? ":-x" : $list['StringyChat_message'];
// while there are rows to be fetched...
while ($list = mysql_fetch_assoc($result)) {
   // echo data
   echo '<span style="color:#828282">' . '(' . date( 'D H:i:s', $list['StringyChat_time'] )  . ') ' . '</span>' . '' . $list['StringyChat_name'] . '' . ' : ' . $pmsg . '<br />';
} // end while

but now I get error Fatal error: Call to undefined function aray() in /home/u506124311/public_html/ag/page.php on line 44

ChauhanAjay 29-Aug-14 6:40am

$bwords = aray("admin", "mod");
To
$bwords = array("admin", "mod");