how to populate a 2D array in C#?

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i'm trying to populate a 2d array in c# using random values .. i've stucked...here is my code

C#

Random random = new Random();
int[ , ] numbers = new int[ no_of_rows , no_of_columns ];

 int row_value = 0;
 int column_value = 0;

// populating 2D Array

for (int m = 0; m < 5 ; m++)
{
    for (int n = 0; n < 5 ; n++)
    {
        row_value = random.Next(0,25);
        column_value = random.Next(0, 25);
        numbers[m,n] = [row_value,column_value];
    }
}

Posted 20-Sep-14 18:09pm

Ammar Shaukat

Updated 20-Sep-14 18:28pm

ChauhanAjay

v2

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BillWoodruff · Accepted Answer · 2014-09-20T21:25:00

C#

// random integer returned can include this value
private const int randMinimum = 0;

// note that random integer returned maximum value will be 
// one less than the value specified: i.e., in this case, #25
private const int randMaximum = 26;

private const int no_of_rows = 5;
private const int no_of_columns = 5;

// fancy way of getting more randomness than you will probably ever need
private Random random = new Random(Guid.NewGuid().GetHashCode());

private int[ , ] numbers = new int[ no_of_rows , no_of_columns ];

// populating 2D Array        
for (int row = 0; row < no_of_rows; row++)
{
    for (int column = 0; column < no_of_columns; column++)
    {
        numbers[row, column] = random.Next(randMinimum, randMaximum);
    }
}

ChauhanAjay · Accepted Answer · 2014-09-20T18:36:00

Solution 1

Try the below code

C#

Random random = new Random();
int[ , ] numbers = new int[5,5];
//populating 2D Array
for (int m = 0; m < 5 ; m++)
{
    for (int n = 0; n < 5 ; n++)
    {
        numbers[m,n] = random.Next(0, 25);
    }
}

Hope it helps

Posted 20-Sep-14 18:36pm

ChauhanAjay

Comments

ChauhanAjay 21-Sep-14 1:48am

Why is the answer downvoted?
Can anybody tell me what is wrong in the answer?

Ammar Shaukat 21-Sep-14 3:23am

thanks.. it is working...

BillWoodruff 21-Sep-14 3:33am

+5 this is a working answer, and it should not have been down-voted !