How to create sub-child using XElement?

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I am writing to seek some guide, as I am currently struggling, in how can I create the following XML using the XElement class,

XML

HTML

<job> 
 <to> 
 <target_type>#######</target_type>
 <targets>
 <target>#####</target> 
 </targets>  
 </to> 
 </job>

C#

XElement xeRoot = new XElement("job");
XElement xeSendTo = new XElement("to");
            xeSendTo.Add(new XElement("target_type", "email_address"),
             
            xeSendTo.Add(new XElement("targets"),
                         new XElement("target", "ma@domain.com")));
            xeRoot.Add(xeSendTo);

I am currently experiencing --> The best overloaded method match for 'System.Xml.Linq.XContainer.Add(params object[])' has some invalid arguments --> error.

Any advice, would be very much helpful.
Many thanks.

Posted 25-Sep-14 0:37am

miss786

Updated 25-Sep-14 0:52am

v2

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george4986 · Accepted Answer · 2014-09-25T00:49:00

Solution 1

try this

C#

XElement xeRoot = new XElement("job");
           XElement xeSendTo = new XElement("to");
           xeSendTo.Add(new XElement("target_type"));
           xeSendTo.SetElementValue("target_type", "#######");
           XElement xeSendTo1 = new XElement("targets");
           xeSendTo1.Add(new XElement("target"));
           xeSendTo1.SetElementValue("target", "##### ");
           xeSendTo.Add(xeSendTo1);
           xeRoot.Add(xeSendTo);

good luck ;-)

Posted 25-Sep-14 0:49am

george4986

Updated 25-Sep-14 1:12am

v2

Comments

george4986 25-Sep-14 6:52am

reference

http://msdn.microsoft.com/en-us/library/system.xml.linq.xelement(v=vs.110).aspx

miss786 25-Sep-14 6:56am

Thank you for your response. I am trying to get the <target> tag under the <targets> tag. I am little unclear how to do this and would you know a specific method within XElement class, I could use to achieve this. Many thanks.

george4986 25-Sep-14 6:59am

do u need value inside tag like search?

miss786 25-Sep-14 7:03am

I would like the "target_type" & "target" nodes to have values. Thanks.

george4986 25-Sep-14 7:13am

updated the solution plz check

miss786 25-Sep-14 9:28am

Apology for the late reply. This great, exactly what I was look for. Many thanks for your time and support. Have a great day/evening! :)

george4986 25-Sep-14 12:37pm

u r always welcome ;-)