How do I write a f statement that will exclude numbers less than 21

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1.00/5 (2 votes)

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C++

#include <iostream>
using namespace std;

int main() {
   const int NUM_ELEMENTS = 8; // Number of elements
   int userVals[NUM_ELEMENTS]; // User numbers
   int i = 0;                  // Loop index
   
   
   // Prompt user to populate array
   cout << "Enter " << NUM_ELEMENTS << " integer values..." << endl;

   for (i = 0; i <= NUM_ELEMENTS; ++i) {
      cout << "Value: " << endl;
      cin >> userVals[i];
   }
   
   // Determine values greater than 21
   for (i = 0; i <= NUM_ELEMENTS; ++i) {
      if   //This is where I am stuck.....
        cout << endl << userVals[i] << endl;
   }
   
   return 0;
}

Posted 14-Oct-14 12:53pm

Member 11153652

Updated 14-Oct-14 13:22pm

Nelek

v6

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Nelek · Accepted Answer · 2014-10-14T13:24:00

You are giving the entered inputs to every place in the array with the first for. Which means userVals[i] is the place where you are saving the info.
To know if the entered numbers are bigger than 21, you have to compare them (logically) and you know where they are saved. Don't you? At the end, a position of the array can be considered as the variable you are asking in that moment.

I mean, in the concept of comparison there is no difference with

C++

int a = 1;
if (a > 0)

//  or

int a = 1
int b = 2
if (a > b)

in conclusion...

C++

for (i = 0; i <= NUM_ELEMENTS; ++i) {
   if (userVals[i] > 21)  // or if (userVals[i] >= 22)
     cout << endl << userVals[i] << endl;
}