what is the mistake in this program? it shows general protection fault error

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C#

#include<stdio.h>
void main()
{

    char name[30];
    int i;

    printf("Enter ur name:\n");
    for(i=0;i<30;i++)
    scanf("%s",&name[i]);



    for(i=0;i<30;i++)
    printf("The name is :%s",name[i]);
}

Posted 15-Oct-14 2:56am

Maverick Mishra

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cp-4711 15-Oct-14 10:46am

I think You want to read 30 names?
But You have only space for one name in the length of 30

2 solutions

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W∴ Balboos, *GHB* · Answer 1 · 2014-10-15T04:26:00

Solution 1

You're printf statement is using %s, which is for ASCIIZ strings and you are printing individual characters name[i] - which are being treated as pointers to a string in the "who knows where" of your O/S

either printf("%s", name);
or printf("%c", name[i]); // for your loop

Posted 15-Oct-14 4:26am

W∴ Balboos, GHB

cp-4711 · Answer 2 · 2014-10-15T04:46:00

C#

// wf-protection-fault-error.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"
#include<stdio.h>

const int max_namecount   =5;   // 5 names
const int max_namelength  =50;  // each name has space for 50 chars

int main(int argc, char *argv[]) 
{
    char name[max_namecount][max_namelength+3];
    int i;

    printf("Enter your name:\n");
    for(i=0;i<max_namecount;i++)  scanf("%50s",name[i]); // 50=max_namelength:  makes sure, that you do not read more chars than you have space in name

    getc(stdin); // only for pause
    for(i=0;i<max_namecount;i++)  printf("\nThe name is :%s",name[i]);

    getc(stdin); // only for pause
      return 0;
}