How To Make Call To Methods Asynchronous.I Have Three Methods Which I Need To Call Asynchronously.

Question

2.00/5 (1 vote)

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.NET3.5

SQL

 public void computeABC()
        {
           /*this is dummy code  , computeA(),computeB(),computeC() needs to be called asynchronously  the result of this fuctions will be input to computeResult() */


            objMyClassA = computeA(); //
            objMyClassB = computeB();
            objMyClassC = computeC();

            computeResult(objMyClassA, objMyClassB, objMyClassC);

        }

public MyClassA  computeA ()
{

     /* database call */
}
public MyClassB  computeB ()
{

    /* database call */
}
public MyClassC  computeC ()
{

    /*database call */
}

Posted 24-Feb-15 17:28pm

mahadevkarekar

Updated 24-Feb-15 17:49pm

v2

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Sergey Alexandrovich Kryukov 24-Feb-15 23:35pm

Asynchronous relative to what? Each other, something else? why?
—SA

mahadevkarekar 24-Feb-15 23:42pm

As seen in code i have 3 methods . computeA() ,computeB() ,computeC(). all this 3 methods perform heavy database operations. so i need to call all this 3 method at one time.

Sergey Alexandrovich Kryukov 25-Feb-15 6:35am

It explains why would you need to call them in parallel to, say, main thread, UI thread, but it does not explain "one time". You could call them in sequence.
—SA

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Joan Magnet · Accepted Answer · 2015-02-24T21:23:00

Solution 1

You should launch a new Thread for every function and use a Semaphore or an AutoResetEvent to let the main thread awaiting for code completion.

There is an example here: MSDN AutoResetEvent

Posted 24-Feb-15 21:23pm

Joan Magnet

Comments

Sergey Alexandrovich Kryukov 25-Feb-15 6:37am

All right, do it. Or use a separate thread. Only don't listen to this "answer".
—SA

Joan Magnet 25-Feb-15 7:44am

Well, look at this sample then. it uses Task.WhenAll to wait for more than one task.

https://msdn.microsoft.com/en-us/library/hh556530.aspx

Sergey Alexandrovich Kryukov 25-Feb-15 6:36am

Do you mean you want to block the main thread for waiting? No kidding?
—SA