Game of Dice with 9 Random Rolls in Java

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Java

game

Hi everyone,

I need to implement a game GameOfDice to be played by two players. Each player gets to roll a  die. The player who rolls the highest wins that round. A player has to win three rounds to  win the game. A game can have at most nine rolls for each player. After the ninth roll, if no  one wins, the game ends and it’s a draw. [Hint: You may generate nine random rolls for each  player, for example: Random number for Player1 is 345612312, and then the first  move of Player1 is 3, next is 4 and so on. The same follows for Player2].

Implement methods:

game_on() – accepts two player objects

get_move() – get the move for a player for the corresponding round.

You may use additional method to generate the moves. 

Sample Output: 

Player1's Move: 4 

Player2's Move: 3 

Player1's Move: 2 

Player2's Move: 1 

Player1's Move: 1 

Player2's Move: 2 

Player1's Move: 2 

Player2's Move: 3 

Player1's Move: 6 

Player2's Move: 2 

Winner is Player1 

So far, I have tried to generate the dice but I need 9 random rolls from (anywhere 1 through 6) and player with the first 3 games wins, if 9 draw. I'm having trouble with the aforementioned methods where the players are created and the rolls are parsed as individual moves.

import java.util.*;
    public class Dice {
     
    	// Creating an object from the class "Random" to be able to use the "Random Number" generator.
    	Random generator = new Random();
     
    	// Public instance variable called "thro" to store in it the randomly numbers.
    	public int thro;
     
    	// Data member "Length", of type "Integer". To get the length of the dice.
    	private int length;
     
    	// get method to get the vd