How to find a pixel which is inside rectangular area or not

Question

1.00/5 (1 vote)

See more:

For eg i have a image of 1280*720 width and height. How to find a particular pixel contains inside x0,y0,x1,y1 co-ordinate

x0,y0
+--------+
|        |    
|        |    
|     .  |    
|        |    
|        |
+--------+x1,y1

Will below algirthm work

C#

typedef struct {
    int left;
    int top;
    int right;
    int bot;
} rect;

int inrect (int x, int y, rect r) {
    if (x<r.left || x>r.right || y<r.top || y>r.bot)
        return 0;
    return 1;
}
rect rectarr[1] = { {10, 10, 50, 50}}

Here 0 means outside and 1 means inside

Posted 16-Mar-15 9:14am

rahul15001

Add a Solution

Comments

Mehdi Gholam 16-Mar-15 15:15pm

Try and see.

Sergey Alexandrovich Kryukov 16-Mar-15 15:24pm

What prevents your from running it? What prevents you from using the debugger is you are not sure what's going on?
—SA

1 solution

Add a Solution

Add your solution here

Treat my content as plain text, not as HTML

Preview 0

…

Existing Members

Sign in to your account

...or Join us

Download, Vote, Comment, Publish.

Your Email
Password
Forgot your password?

Your Email
This email is in use. Do you need your password?
Optional Password

I have read and agree to the Terms of Service and Privacy Policy
Please subscribe me to the CodeProject newsletters

When answering a question please:

Read the question carefully.
Understand that English isn't everyone's first language so be lenient of bad spelling and grammar.
If a question is poorly phrased then either ask for clarification, ignore it, or edit the question and fix the problem. Insults are not welcome.
Don't tell someone to read the manual. Chances are they have and don't get it. Provide an answer or move on to the next question.

Let's work to help developers, not make them feel stupid.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

CPallini · Answer 1 · 2015-03-16T10:25:00

Solution 1

Yes, it would work. However, for performance reasons, relatively big structs are usually passed via pointers (see, for instance, PtInRect Windows function signature)

C

int inrect (int x, int y, const rect *pr) {
    if (x<pr->left || x>pr->right || y<pr->top || y>pr->bot)
        return 0;
    return 1;
}

Posted 16-Mar-15 10:25am

CPallini

Comments

Sergey Alexandrovich Kryukov 16-Mar-15 16:29pm

Good point, a 5.
—SA

CPallini 16-Mar-15 16:43pm

Way too good man, thank you anyway :-)