XML deserialization for derived objects.

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How deserialize document XML:
---------------------------------------------

HTML

<something id=""234"">
     <items>
          <item name=""Obj1"">
               <a>1</a>
               <k>1</k>
          </item>
          <item name=""Obj2"">
                <c>5</c>
                <d>2</d>
                <e>1</e>
           </item>
     </items>
</something>

I can't get value elemnts in item
---------------------------------------------

C#

[XmlRoot("something")]
    public class Something: ClassBase
    {
       [XmlAttribute("id")]
        public string id;

       [XmlArray("items")]
       public ItemsCollection forms { set; get; } 

       public Something(): base() { }
    }


    [XmlType("item")]
    public class ItemsCollection: CollectionClassBase<Item>
    {
        public ItemsCollection() : base() { }
    }


    [XmlType("item")]
    public class Item: ClassBase
    {
        [XmlAttribute("name"), DefaultValue("")]
        public string name { set; get; }
    }

    [XmlType("item")]
    public class ItemObj1 : Item
    {
        [XmlElement("a"), DefaultValue("")]
        public string a  { set; get; }
        [XmlElement("b"), DefaultValue("")]
        public string b { set; get; }
    }

Posted 17-Mar-15 23:43pm

Member 10294936

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Maciej Los · Answer 1 · 2015-03-18T00:06:00

Solution 1

I'd suggest to use xsd.exe tool[^] which can generate proper class(es) definition from xml.

Follow these steps: Auto generating Entity classes with xsd.exe for XML Serialization and De-Serialization[^]

[EDIT]
I'd suggest to change your XML structure:

XML

<something id="234">
     <items>
          <item name="Obj1">
               <a>1</a>
               <k>1</k>

to:

XML

<something id="234">
     <items>
          <item name="Obj1">
               <property name="a">1</a>
               <property name="k">1</k>

It should help you while XML normalization.
[/EDIT]

Posted 18-Mar-15 0:06am

Maciej Los

Updated 18-Mar-15 5:56am

v2

Comments

Member 10294936 18-Mar-15 10:59am

Thanks for your reaply.
I use xsd.exe tool. After create XSD I see that item have all tag a, k, c, d, e.
So I create class and use it:

[XmlType("item")]
public class Item: ClassBase
{
[XmlAttribute("name"), DefaultValue("")]
public string name { set; get; }
[XmlElement("a"), DefaultValue(0)]
public int a { set; get; }
[XmlElement("k"), DefaultValue(0)]
public int k { set; get; }
[XmlElement("c"), DefaultValue(0)]
public int c { set; get; }
[XmlElement("d"), DefaultValue(0)]
public int d { set; get; }
[XmlElement("d"), DefaultValue(0)]
public int d { set; get; }
}

This approach isn't good for me, because in my XML is maybe 1000 fields with value.

BTW My console application deserialization file XML that I receive to my request. This is a cyclical process. Next time I mapping objects to tables in database and save data.

Maciej Los 18-Mar-15 11:57am

I think you should change XML structure (and related class) - if you can...
Please, see updated answer ;)

Member 10294936 18-Mar-15 11:06am

-- duplicate --

Member 10294936 19-Mar-15 7:01am

I can't change XML (only receve from another application).
XSD.exe is helpful for me, because in XML is to many fileds that create class manualy.
Next time I save data to database use TableAdapters.

Thanks a lot, regards, pozdrawiam :)
Małgorzata

Maciej Los 19-Mar-15 7:30am

You're very welcome ;)
Cheers, Pozdrawiam, Maciej