how to pass a php variable in anchor tag?

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<?php foreach ( $fields as $name => $value ):

        if ( $name == 'Venue' ):
        ?>


        <dt> <?php echo " <a href=''>" $name "</a>" ?> </dt>

        <dd class="tribe-meta-value"> <?php  $value ?> </dd>
        <?php endif ?>

         <?php endforeach ?>

variable $fields is contains two variables $name and $value.
$name is the venue.
$value is the address of that venue i.e. it is a web address. and is entered by the user.
on output screen only the name of the venue will be displayed which will be a hyperlink..which on click must redirect the user to the venue page.

Posted 28-Mar-15 20:50pm

Member 11563816

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Arkadeep De 29-Mar-15 3:19am

I am not a php expert but still its a try to solve this one. If I am wrong please don't mind.
Is your variable $value contains value like 'http://abc.com.xyz' then I think
" $name " will do the work.

Member 11563816 29-Mar-15 3:33am

Please change in my code and paste it.. then i will try.

Arkadeep De 29-Mar-15 3:40am

Bro I had put the whole code of anchor in the comment. but it is taking the code as a real anchor tag. just put $value as href='"$value"'.

Member 11563816 29-Mar-15 3:47am

i had already tried this.. its not working.
showing forbidden error screen

2 solutions

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Peter Leow · Answer 1 · 2015-03-28T22:04:00

Solution 1

Two mistakes:
1. you did not concatenate the $name using ".", like this:

<?php echo " <a href=''>".$name."</a>" ?>

2. you did not echo the $value, like this:

<?php echo $value ?>

Posted 28-Mar-15 22:04pm

Peter Leow

Updated 29-Mar-15 5:25am

v4

Comments

Member 11563816 29-Mar-15 5:45am

if i will echo $value then it will print the value of $value on the output screen below the value of $name.

Peter Leow 29-Mar-15 7:44am

Correct. That are the working of dt and dd. You can google for the meaning of them. I will take it that I have solved your problem.

ramyajaya · Answer 2 · 2015-03-29T04:44:00

Solution 2

Here in solution 1 there is a small typo error

PHP

?<php echo " <a href=''>
".$name."</a>" ?>

Which is

PHP

<?php echo " <a href=''>".$name."</a>" ?>

Instead of this you can do like this

PHP

<a href="<?php echo $value ?>"><?php $ name?></a>

As you have mentioned $ value is the address it should be the href and $ name is the display value

Hope it helps

Posted 29-Mar-15 4:44am

ramyajaya

Updated 29-Mar-15 4:54am

v2

Comments

Peter Leow 29-Mar-15 11:27am

Thank you, ramyajaya. Corrected the typo.