storing ListBox items into a database

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Sir If i want to store the list-box selected items into one column(i.e interests) of table where already few records are there like username, id,city,country and i want to add one more column i.e interests(which is a list-box) and user who is logged in when select some interests .i want it to be added in that interest column for a particular user, and in a separate row.

I have tried, the interests that user is selecting from list-box is storing in a table.But it not for the logged in user.It is displayed on the next row with all the other columns as Null values.My table looks like this:

UserName       Id      city     country   pin-code       interests
NULL           NULL    NULL     NULL      NULL           privacy,protection

instead I want all the above user fields as the logged on user details.

Posted 22-Apr-15 13:25pm

Member 11505979

Updated 22-Apr-15 19:58pm

Maciej Los

v2

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Gideon van Dyk 22-Apr-15 21:13pm

A segment of the code used to try and persist the data to the DB will aid in getting a clearer answer.

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Abhinav S · Answer 1 · 2015-04-22T20:11:00

Solution 1

Don't store interests as comma separate values.
Store each interest as a new row.

This is known as first normal form[^] during normalization of a relational database.

Posted 22-Apr-15 20:11pm

Abhinav S

v2

Member 11505979 · Answer 2 · 2015-04-23T09:50:00

I have written code like this, it stores the listbox items for particular user, but it is updating the items in listbox.Like when i select 2 items....for eg: privacy, php its showing only php....i.e the current selected item....

SqlConnection conn = new SqlConnection(ConfigurationManager.ConnectionStrings["RegistrationConnectionString"].ConnectionString);

SqlCommand cmd = conn.CreateCommand();

C#

foreach(ListItem item in ListBoxadditems.Items) // to store the values of listboxitems into database as per logged in user
            {

SQL

conn.Open();
                   cmd.CommandText ="UPDATE UserData SET Interests='"+item.Text+"' WHERE UserName='"+Session["New1"]+"'";

C#

cmd.ExecuteNonQuery();
                         Label5.Text = "Data Inserted";
                         conn.Close();

}