Click here to Skip to main content
15,885,546 members
Please Sign up or sign in to vote.
0.00/5 (No votes)
1-
SQL
TRANSFORM Sum(ISSUE.Qty_issue) AS [The Value]
SELECT ISSUE.[Tag_no], Sum(ISSUE.Qty_issue) AS [Total Of Qty_issue]
FROM ISSUE
GROUP BY ISSUE.[Tag_ no]
PIVOT ISSUE.Tmpe;


2-
SQL
TRANSFORM Sum(MRV.[Ret-qty]) AS [The Value]
SELECT MRV.[Tag_ no], Sum(MRV.[Ret-qty]) AS [Total Of Ret-qty]
FROM MRV
GROUP BY MRV.[Tag_ no]
PIVOT MRV.TEMP;


3-
SQL
TRANSFORM Sum(REC.[Rec-qty]) AS [The Value]
SELECT REC.[Tag_ no], Sum(REC.[Rec-qty]) AS [Total Of Rec-qty]
FROM REC
GROUP BY REC.[Tag_ no]
PIVOT REC.TMPE;
Posted
Updated 25-Apr-15 1:53am
v2

You need to learn about pivot[^].

This set of articles might be helpful:
Simple Way To Use Pivot In SQL Query[^]
How to Perform Pivot Operation in T-SQL..?[^]
SQL - Pivot with Grand Total Column and Row[^]
SQL Pivot and Table Adapter[^]

1. query can be "converted" as follow:
SQL
SELECT [Tag_no], [Val1], [Val2], [Val3]
FROM (
    SELECT ISSUE.[Tag_no], ISSUE.Tmpe, ISSUE.Qty_issue AS [Qty_issue]
    FROM ISSUE
    ) AS DT
PIVOT ((SUM(Qty_issue) FOR Tmpe IN ([Val1], [Val2], [Val3])) AS PVT;


Note: i don't know what kind of data returns ISSUE.Tmpe field. So, you need to replace [Val1], [Val2], [Val3] with proper values.
 
Share this answer
 
list all field in tabel ISSUE

SQL
SELECT ISSUE.[Tag_ no], ISSUE.[Miv_ no], ISSUE.Qty_issue, ISSUE.[TT-73_no], ISSUE.Qty_issue, ISSUE.[TT-73_no], ISSUE.[Rec_ by], ISSUE.[Iso_ no], ISSUE.Double, ISSUE.Tmpe
FROM ISSUE;
 
Share this answer
 
Comments
Maciej Los 25-Apr-15 8:31am    
This is not an answer. Please, delete it to avoid down-voting.

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)



CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900