How many address lines are needed to address each machine location in a 1024x8 Memory chip?

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please tell me the procedure to solve data bus and address bus related questions.

Posted 17-May-15 6:22am

dipankarnalui

Updated 17-May-15 6:41am

Frankie-C

v2

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Solution 1

This seems an homework, and we don't do homeworks for you.
Just a hint to access 1024 cells (each 8 bits wide) you need a number of address lines that counts up to 1024 in binary (consider an address line a binary digit).
If you can't solve after this suggestion maybe you want reconsider if IT is your right study field...

Posted 17-May-15 6:39am

Frankie-C

v2

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dipankarnalui · Accepted Answer · 2015-05-17T18:53:00

Solution 2

1024 x 8 means number of memory location = 1024. if number of address lines =n then 2^n = location... that is here 2^n = 1024 ..we have to find n ? n = 10 .. so number of address lines is 10. is it correct sir ?

Posted 17-May-15 18:53pm

dipankarnalui