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How to get Present Logical Drives (the bitwise way)

, 19 Dec 2010 CPOL 3.3K 3
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Forget all that "C" old bit operator, you are "C++", use the modern STL way ;) #include #include void PrintLogicalDrives(){ using namespace std; bitset lt ld = (int)GetLogicalDrives(); for( char i = 'A'; i <= 'Z'; i++ ) { ...
Forget all that "C" old bit operator, you are "C++", use the modern STL way Wink | ;)

#include <bitset>
#include <iostream>
 
void PrintLogicalDrives()
{
    using namespace std;
    bitset lt< 'Z' - 'A' + 1 > ld = (int)GetLogicalDrives();
    for( char i = 'A'; i <= 'Z'; i++ )
    {
        if( ld[ i - 'A' ] )
            cout << i << ":" << endl;
    }
}

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This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

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About the Author

jean Davy
Engineer
France France
I'm an independent Software Developer living in the Alpes Maritimes (aka French Riviera).

Even if in the past I have worked regularily with Fortran, Pascal, Basic (not necessarily Visual), and much more esoteric languages (who knows Prolog, Lotus 123 macros ?), even if I still work from time to time with C#, Java or some "interpreted languages", I'm more specialized in C++.
I work on MFC since the very first version, I enjoy working on Visual Studio 2010, its C++0x features, STL, MFC, boost, WTL ...

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Comments and Discussions

 
GeneralReason for my vote of 5 Good answer. Pin
Alain Rist18-Dec-10 6:08
memberAlain Rist18-Dec-10 6:08 

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