How to get Present Logical Drives (the bitwise way)

#include <bitset>
#include <iostream>

void PrintLogicalDrives()
{
    using namespace std;
    bitset lt< 'Z' - 'A' + 1 > ld = (int)GetLogicalDrives();
    for( char i = 'A'; i <= 'Z'; i++ )
    {
        if( ld[ i - 'A' ] )
            cout << i << ":" << endl;
    }
}

I'm an independent Software Developer living in the Alpes Maritimes (aka French Riviera).

Even if in the past I have worked regularily with Fortran, Pascal, Basic (not necessarily Visual), and much more esoteric languages (who knows Prolog, Lotus 123 macros ?), even if I still work from time to time with C#, Java or some "interpreted languages", I'm more specialized in C++.
I work on MFC since the very first version, I enjoy working on Visual Studio 2010, its C++0x features, STL, MFC, boost, WTL ...