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Convert Datatable to Collection using Generic

By , 13 Aug 2011
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Very nice!
 
I've modified ToCollection(this DataTable dt) extension function, so if DataTable column names and class property names are different, then you can use this alternative:
 
public static List<t> ToCollection<t>(this DataTable table, Dictionary<string,> dic)
{
    List<t> lst = new System.Collections.Generic.List<t>();
    Type classType = typeof(T);
    PropertyInfo[] propertyInfoList = classType.GetProperties();
    List<datacolumn> columnsList = table.Columns.Cast<datacolumn>().ToList();
    T t;
    foreach (DataRow item in table.Rows)
    {
        t = (T)Activator.CreateInstance(classType);
        foreach (PropertyInfo oneInfo in propertyInfoList)
        {
            try
            {
                DataColumn d = columnsList.Find(col => col.ColumnName == dic[oneInfo.Name]);
                if (d != null) oneInfo.SetValue(t, item[dic[oneInfo.Name]], null);
            }
            catch
            {
            }
        }
        lst.Add(t);
    }
    return lst;
}</datacolumn></datacolumn></t></t></t></t>
 
Class
 
public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
}
 

DataTable
 
public DataTable getTable()
{
    DataTable dt = new DataTable();
    dt.Columns.Add(new DataColumn("FIRST_NAME", typeof(string)));
    dt.Columns.Add(new DataColumn("LAST_NAME", typeof(string))); 
    DataRow dr;
 
    for (int i = 1; i < 11; i++)
    {
        dr = dt.NewRow();
        dr["FIRST_NAME"] = "First Name" + i;
        dr["LAST_NAME"] = "Last Name" + i;
        dt.Rows.Add(dr);
    }             
    return dt;
}
 
Convertion
 
DataTable table = getTable();
Dictionary<string,> dic = new Dictionary<string,>();
dic.Add("FirstName", "FIRST_NAME");
dic.Add("LastName", "LAST_NAME"); 
List<person> lst = table.ToCollection<person>(dic);</person></person>

License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

About the Author

Vano Maisuradze
Software Developer (Senior)
Georgia Georgia
No Biography provided

Comments and Discussions

 
GeneralReason for my vote of 5 I really liked it!! PinmemberAnurag Gandhi23-Aug-11 2:07 

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