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A simple program to solve quadratic equations with

By , 8 Nov 2010
 
Simple and prints imaginary roots too!
float a,b,c,x1,x2,d,dsq;
printf("ax^2 + bx + c = 0");
printf("\nEnter a,b,c separated by commas : \n");
scanf("%f,%f,%f",&a,&b,&c);
d = b*b-(4*a*c);
if(d>=0)
{
dsq=sqrt(d);
x1 = (-b+dsq)/(2*a);
x2 = (-b-(dsq))/(2*a);
printf("\nRoot 1 : %f\nRoot 2 : %f",x1,x2);
}
if(d<0)
{
d = ((4*a*c)-pow(b,2))/(2*a);
printf("\nRoot 1 : %f+%fi",((-b)/(2*a)),d);
printf("\nRoot 2 : %f-%fi",((-b)/(2*a)),d);}

License

This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

About the Author

Anshul R
Student
India India
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GeneralReason for my vote of 2 Inefficient and does not handle divi...memberAndrew Phillips7 Nov '10 - 15:19 

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