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A simple program to solve quadratic equations with

, 8 Nov 2010 CPOL
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Simple and prints imaginary roots too!float a,b,c,x1,x2,d,dsq;printf("ax^2 + bx + c = 0");printf("\nEnter a,b,c separated by commas : \n");scanf("%f,%f,%f",&a,&b,&c);d = b*b-(4*a*c);if(d>=0){dsq=sqrt(d);x1 = (-b+dsq)/(2*a);x2 = (-b-(dsq))/(2*a);printf("\nRoot 1 : %f\nRoot 2...
Simple and prints imaginary roots too!
float a,b,c,x1,x2,d,dsq;
printf("ax^2 + bx + c = 0");
printf("\nEnter a,b,c separated by commas : \n");
d = b*b-(4*a*c);
x1 = (-b+dsq)/(2*a);
x2 = (-b-(dsq))/(2*a);
printf("\nRoot 1 : %f\nRoot 2 : %f",x1,x2);
d = ((4*a*c)-pow(b,2))/(2*a);
printf("\nRoot 1 : %f+%fi",((-b)/(2*a)),d);
printf("\nRoot 2 : %f-%fi",((-b)/(2*a)),d);}


This article, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)


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Anshul R
India India
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Comments and Discussions

GeneralReason for my vote of 2 Can crash too ! Pin
YvesDaoust9-Nov-10 0:27
memberYvesDaoust9-Nov-10 0:27 
Generalthats the most basic rule in the book Pin
JFergulbops8-Nov-10 23:38
memberJFergulbops8-Nov-10 23:38 
General1) It doesn't matter what the real world quadratic equations... Pin
Silic0re098-Nov-10 5:34
memberSilic0re098-Nov-10 5:34 
GeneralThank you for the suggestion.. I do not wish to be rude. If... Pin
pranav958-Nov-10 1:13
memberpranav958-Nov-10 1:13 
GeneralReason for my vote of 2 Inefficient and does not handle divi... Pin
Andrew Phillips7-Nov-10 16:19
memberAndrew Phillips7-Nov-10 16:19 
GeneralThis is better than the others as you avoid the domain error... Pin
Andrew Phillips7-Nov-10 16:14
memberAndrew Phillips7-Nov-10 16:14 
This is better than the others as you avoid the domain error in sqrt(). A couple of things:
- pow(b, 2) is better written as b*b
- it's probably better not to evaluate sqrt(d) twice
- the original returned two floats, you should return an error instead of complex numbers

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