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IntroductionThis article describes how to display images which are stored in a database. You can use For example: <IMG SRC="ShowPicture.asp?PhotoId=1">
where Using the codeFollowing are the steps which needs to be executed:
Create table with the following structure: Table name: Users
CodeShowPicture.asp is used to display images. You need to pass user ID in querystring, and for that user ID, image will be displayed. Following is the code: 'Declare Variables..
Dim sql
Dim rs
Dim conn
Dim userID,str
userID = Request("PhotoId")
If userID = "" Then userID = 0
'Instantiate Objects
Set conn = Server.CreateObject("ADODB.Connection")
Set rs = Server.CreateObject("ADODB.Recordset")
'Open connection
Conn.Open "Provider=Microsoft.Jet.OLEDB.4.0;" & _
"Data Source=" & Server.MapPath("data.mdb")
'Get the specific image based on the ID passed in a querystring
str = "SELECT user_photo FROM users where user_id =" & userID
rs.Open str, conn,3,3
if rs.eof then 'No records found
Response.End
else 'Display the contents
Response.ContentType = "image/gif"
Response.BinaryWrite(rs("user_photo"))
end if
'destroy the variables.
rs.Close
conn.Close
set rs = Nothing
set conn = Nothing
Please note that " Response.ContentType = "image/jpg"
To use above page for displaying images, following is the example: <IMG SRC="ShowPicture.asp?PhotoId=1">
<IMG SRC="ShowPicture.asp?PhotoId=2">
Upload ImageFollowing example shows how to upload images in database by using Following is the code to upload image: <FORM METHOD="POST" ACTION="saveFile.asp"
ENCTYPE="multipart/form-data" NAME="UploadForm">
<center>
Employee Name : <INPUT TYPE="TEXT" NAME="USERNAME" SIZE="30"><br>
<INPUT TYPE="FILE" NAME="UPLOADFILE1" SIZE="50">
</center>
<BR>
<center><INPUT TYPE="SUBMIT" VALUE="Upload"
id=SUBMIT1 name=SUBMIT1></center>
</FORM>
Code to save the image in the database: Dim myupload
'declare variables..
intCount=0
' Create Upload Component
Set myupload = Server.CreateObject("aspSmartUpload.SmartUpload")
myupload.Upload
'Create Connection
Set Conn = Server.CreateObject("ADODB.Connection")
Conn.Open "Provider=Microsoft.Jet.OLEDB.4.0;" & _
"Data Source=" & Server.MapPath("data.mdb")
Set Rs = Server.CreateObject("ADODB.recordset")
Rs.Open "SELECT user_id,user_name,user_photo FROM users", Conn,3,3
'Select each file
For each file In myupload.Files
If not file.IsMissing Then 'Check for missing file
'Add the current file in database
Rs.AddNew
file.FileToField Rs.Fields("user_photo")
Rs("user_name") = myupload.Form("USERNAME")
Rs.Update
intCount = intCount + 1
End If
Next
Response.Write(intCount & " file(s) uploaded.")
'Destroy the objects...
CommentsIt is always better to store images in the file system rather than storing in the database. Only image path can be stored in the database. However, storing images in the database depends on requirements and needs.
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