Click here to Skip to main content
Sign Up to vote bad
good
See more: Java
when i trace the code im getting 1,3,5,7 for the answer but the compiler prints 1,3,6,10
im having trouble understanding how this happens could anyone explain
 
int [] a= new int[5];  // create array
for (int i =1; i<=4; i++)    
{
  a[i]=a[i-1]+i;
  System.out.print(a[i]+" ");
}
Posted 10 Nov '12 - 12:32
Edited 10 Nov '12 - 13:23
TorstenH.29.4K

Comments
Nelek - 10 Nov '12 - 18:44
What I can not understand is where you get 1,3,5,7. The result of this code is what the compiler prints.

1 solution

when i trace the code
 
You debug it. While debugging you figure several operations in one line:
 
for (int i =1; i<=4; i++)    
{
  a[i]=a[i-1]+i;
  System.out.print(a[i]+" ");
}
 
should be
 
for (int i =1; i<=4; i++)    
{
  int iNumber = a[i-1]; // get number of previous field
  iNumber += i; // add counter
  a[i]=iNumber; // place result
  System.out.print(a[i]+" ");
}
 
This way you can figure every step and see that the output if this is "1 3 6 10".
  Permalink  
Comments
Sergey Alexandrovich Kryukov - 11 Nov '12 - 1:10
5ed. --SA

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)

  Print Answers RSS
Your Filters
Interested
Ignored
     
0 OriginalGriff 208
1 Maciej Los 156
2 Santhosh G_ 155
3 Richard MacCutchan 145
4 Tadit Dash 140
0 Sergey Alexandrovich Kryukov 10,264
1 OriginalGriff 7,937
2 CPallini 4,201
3 Rohan Leuva 3,522
4 Maciej Los 3,135


Advertise | Privacy | Mobile
Web04 | 2.6.130523.1 | Last Updated 10 Nov 2012
Copyright © CodeProject, 1999-2013
All Rights Reserved. Terms of Use
Layout: fixed | fluid