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when i trace the code im getting 1,3,5,7 for the answer but the compiler prints 1,3,6,10
im having trouble understanding how this happens could anyone explain
 
int [] a= new int[5];  // create array
for (int i =1; i<=4; i++)    
{
  a[i]=a[i-1]+i;
  System.out.print(a[i]+" ");
}
Posted 10-Nov-12 12:32pm
Edited 10-Nov-12 13:23pm
TorstenH.32.6K
v2
Comments
Nelek at 10-Nov-12 18:44pm
   
What I can not understand is where you get 1,3,5,7. The result of this code is what the compiler prints.

1 solution

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Solution 1

when i trace the code
 
You debug it. While debugging you figure several operations in one line:
 
for (int i =1; i<=4; i++)    
{
  a[i]=a[i-1]+i;
  System.out.print(a[i]+" ");
}
 
should be
 
for (int i =1; i<=4; i++)    
{
  int iNumber = a[i-1]; // get number of previous field
  iNumber += i; // add counter
  a[i]=iNumber; // place result
  System.out.print(a[i]+" ");
}
 
This way you can figure every step and see that the output if this is "1 3 6 10".
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Comments
Sergey Alexandrovich Kryukov at 11-Nov-12 1:10am
   
5ed.
--SA

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