Click here to Skip to main content
15,885,216 members
Please Sign up or sign in to vote.
1.00/5 (1 vote)
See more:
when i trace the code im getting 1,3,5,7 for the answer but the compiler prints 1,3,6,10
im having trouble understanding how this happens could anyone explain

Java
int [] a= new int[5];  // create array
for (int i =1; i<=4; i++)    
{
  a[i]=a[i-1]+i;
  System.out.print(a[i]+" ");
}
Posted
Updated 10-Nov-12 13:23pm
v2
Comments
Nelek 10-Nov-12 18:44pm    
What I can not understand is where you get 1,3,5,7. The result of this code is what the compiler prints.

1 solution

when i trace the code

You debug it. While debugging you figure several operations in one line:

Java
for (int i =1; i<=4; i++)    
{
  a[i]=a[i-1]+i;
  System.out.print(a[i]+" ");
}


should be

Java
for (int i =1; i<=4; i++)    
{
  int iNumber = a[i-1]; // get number of previous field
  iNumber += i; // add counter
  a[i]=iNumber; // place result
  System.out.print(a[i]+" ");
}


This way you can figure every step and see that the output if this is "1 3 6 10".
 
Share this answer
 
Comments
Sergey Alexandrovich Kryukov 11-Nov-12 1:10am    
5ed.
--SA

This content, along with any associated source code and files, is licensed under The Code Project Open License (CPOL)



CodeProject, 20 Bay Street, 11th Floor Toronto, Ontario, Canada M5J 2N8 +1 (416) 849-8900