Click here to Skip to main content

Comments by Massimiliano Peluso "WeDev Limited" (Top 1 by date)

   
Deleted
Hi thanks for your feedback It doesn't use expression means It doesn't use them for parsing the expression passed as parameter but I just treat it as a string splitting down the full expression body. If I was using the expression in the proper way I would have used the expression class/methods for getting the expression body and the parameters adding lots of overhead. I hope it makes sense

Advertise | Privacy | Mobile
Web04 | 2.8.140415.2 | Last Updated 1 Jan 1900
Copyright © CodeProject, 1999-2014
All Rights Reserved. Terms of Use
Layout: fixed | fluid