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Regex
which can accept alphanumeric with special characters " A-Za-z0-9()[]+-*/%"

/^[ A-Za-z0-9()[]+-*/%]*$/
Posted
Updated 30-Dec-20 21:18pm

1 solution

Escape the ']' inside the list:
/^[ A-Za-z0-9()[\]+-*/%]*$/


If you are going to use Regular Expressions, get a copy of Expresso[^] - it's free, and it examines and generates Regular expressions.
   
v3
Comments
Member-515487 15-Dec-15 7:05am
   
[RegularExpression(@"/^[ A-Za-z0-9()[\]+-*/%]*$/", ErrorMessageResourceType = typeof(ResourceFiles.EntlEngine_Resource), ErrorMessageResourceName = "RuleEditorRegexValidation")]

it not working it giving u run time exception
OriginalGriff 15-Dec-15 7:12am
   
:sigh:
You can't just put the backslash in as part of a javascript string: backslash is an escape character in JS as well, so you would need two of them to pass one through to the Regex parser...
Member-515487 15-Dec-15 7:11am
   
parsing "^[ A-Za-z0-9()[\]+-*/%]*$/" - [x-y] range in reverse order.
Member-515487 15-Dec-15 7:39am
   
@"^[ A-Za-z0-9\[\]()*\-+/%]*$

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