How to generate multiple random numbers within a specific range in ASP.NET C#

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Hello,
Actually i want to generate more than 1 random from given reng od minumum and maximum value from textbox on button click

. aspx..-------------

Minimum value<asp:TextBox ID="TextBox1" runat="server">

Maximum value<asp:TextBox ID="TextBox2" runat="server">

Result : <asp:Label ID="lblnumber" runat="server">
<asp:Button ID="Button1" runat="server"
OnClick="Button1_Click" Text="Generate Random Number in a Rage" />

.cs-----------
protected void Button1_Click(object sender, EventArgs e)
{
//------1
Random r1 = new Random();
int num = r1.Next(
Convert.ToInt32(TextBox1.Text),
Convert.ToInt32(TextBox2.Text)
);
////----- 2
//Random r2 = new Random();
//int num2 = r2.Next(
// Convert.ToInt32(TextBox1.Text),
// Convert.ToInt32(TextBox2.Text)
// );
////----- 2
//Random r3 = new Random();
//int num3 = r3.Next(
// Convert.ToInt32(TextBox1.Text),
// Convert.ToInt32(TextBox2.Text)
// );
////----- 2
//Random r4 = new Random();
//int num4 = r4.Next(
// Convert.ToInt32(TextBox1.Text),
// Convert.ToInt32(TextBox2.Text)
// );
lblnumber.Text = "First No." + num.ToString(); // +", 2nd No." + num2.ToString() + ", No.3 " + num3.ToString() + ", 4th No." + num4.ToString();
//Response.Write(num.ToString());
NewNumber();
}
public Random a = new Random(); // replace from new Random(DateTime.Now.Ticks.GetHashCode());
// Since similar code is done in default constructor internally
public List<int> randomList = new List<int>();
int MyNumber = 0;
private void NewNumber()
{
MyNumber = a.Next(0, 10);
if (!randomList.Contains(MyNumber))
randomList.Add(MyNumber);
}

With is code , i get only one random number on every click, But i want minimum 4 random number .
Please chack and resolve this problem.

What I have tried:

Hello,
 Actually i want to generate more than 1 random  from given reng od minumum and maximum value from textbox on button click
 
 
. aspx..-------------
<div>
Minimum value<asp:TextBox ID="TextBox1" runat="server"></asp:TextBox><br />
Maximum value<asp:TextBox ID="TextBox2" runat="server"></asp:TextBox><br />
<br />
Result : <asp:Label ID="lblnumber" runat="server"></asp:Label>
<asp:Button ID="Button1" runat="server"
OnClick="Button1_Click" Text="Generate Random Number in a Rage" /><br />
</div>
 
 
 
.cs-----------
protected void Button1_Click(object sender, EventArgs e)
{
//------1
Random r1 = new Random();
int num = r1.Next(
Convert.ToInt32(TextBox1.Text),
Convert.ToInt32(TextBox2.Text)
);
////----- 2
//Random r2 = new Random();
//int num2 = r2.Next(
// Convert.ToInt32(TextBox1.Text),
// Convert.ToInt32(TextBox2.Text)
// );
////----- 2
//Random r3 = new Random();
//int num3 = r3.Next(
// Convert.ToInt32(TextBox1.Text),
// Convert.ToInt32(TextBox2.Text)
// );
////----- 2
//Random r4 = new Random();
//int num4 = r4.Next(
// Convert.ToInt32(TextBox1.Text),
// Convert.ToInt32(TextBox2.Text)
// );
lblnumber.Text = "First No." + num.ToString(); // +", 2nd No." + num2.ToString() + ", No.3 " + num3.ToString() + ", 4th No." + num4.ToString();
//Response.Write(num.ToString());
NewNumber();
}
public Random a = new Random(); // replace from new Random(DateTime.Now.Ticks.GetHashCode());
// Since similar code is done in default constructor internally
public List<int> randomList = new List<int>();
int MyNumber = 0;
private void NewNumber()
{
MyNumber = a.Next(0, 10);
if (!randomList.Contains(MyNumber))
randomList.Add(MyNumber);
}
 
 
With is code , i get only one random number on every click, But i want minimum 4 random number .
Please chack and resolve this problem.

Posted 8-Nov-17 0:52am

Vivek VIshwas

Updated 9-Nov-17 1:30am

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Comments

F-ES Sitecore 8-Nov-17 7:00am

Use a "for" loop to execute the code that gets the random number the required number of times.

2 solutions

Solution 2

protected void Button1_Click(object sender, EventArgs e)
    {
        int min, max,v1,v2,v3,v4;
        min = int.Parse(TextBox1.Text);
        max = int.Parse(TextBox2.Text);
        Random r = new Random();
        v1 = r.Next(min,max);
        v2 = r.Next(min,max);
        v3 = r.Next(min, max);
        v4 = r.Next(min, max);
        Label1.Text = v1.ToString()+" "+ v2.ToString() +" "+v3.ToString()+" "+ v4.ToString();

    }

OUTPUT:-

min value 100
max value 220
result 180 137 186 202

Posted 9-Nov-17 1:29am

ashwani bakshi

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OriginalGriff · Accepted Answer · 2017-11-08T01:04:00

First off, don't use Convert for user input: always use TryParse:

C#

int min, max;
if (!int.TryParse(textBox1.Text, out min))
   {
   // Report bad input to user
   return;
   }
if (!int.TryParse(textBox2.Text, out max))
   {
   // Report bad input to user
   return;
   }
for (int i = 0; i < 4; i++)
   {
   randomList.Add(rand.Next(min, max));
   }