how to send 2 dimension array as a parameter to a function

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i can not send 2 dimension array to a function

C#

void fun(int **x);
int _tmain(int argc, _TCHAR* argv[])
{
    int x[5][6];

    for(i=0;i<5;i++)
        for(j=0;j<6;j++)
            x[i][j]=i+j;

        for(i=0;i<5;i++)
        for(j=0;j<6;j++)
            cout<<"x[i][j]="<<x[i][j]<<endl;

        fun(&(x);<-----Error

    return 0;
}
void fun(int **x)
{

.
.
.

Posted 11-Mar-11 5:08am

Khalid Sabtan

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Comments

mbue 11-Mar-11 12:15pm

Use typedef and everything is ok.


typedef int I5x6[5][6];

void func(I5x6& z)
{
  unsigned int  i,j;
  for(i=0;i<5;i++)
  {
    for(j=0;j<6;j++)
    {
      TRACE(__TEXT("%i\r\n"),z[i][j]);
    }
  }
}
void main()
{
  I5x6          ip;
  unsigned int  i,j;
  for(i=0;i<5;i++)
  {
    for(j=0;j<6;j++)
    {
      ip[i][j] = i+j;
    }
  }
  func(ip);
}

4 solutions

Solution 1

You can use fun(x) instead of fun(&x).
You also have one ( too many, the compiler should complain about that though :)

Posted 11-Mar-11 5:36am

User 7429338

v2

Comments

Khalid Sabtan 11-Mar-11 11:40am

fun(x) did not works , i have tried it before i post the question

[no name] 11-Mar-11 11:41am

What is your exact code? I see more errors in this fragment but I ignored them because I thought you did them intentionally to keep things short. For example this program won't work since you use the variables i and j without declaring them.

Nuri Ismail 11-Mar-11 11:55am

Thaddeus, I think that the most serious problem in the code is using pointer-to-pointer to pass two dimensional arrays to function. Please have a look at the links from my answer, especially the first one.

NOTE: This downvote was not from me. I'm actually against downvotes I'd prefer there are only upvotes.

[no name] 11-Mar-11 12:13pm

You are correct, thanks for the link.

Khalid Sabtan 11-Mar-11 12:04pm

i made the code very short,of course i and j is not declared, you could also say where is the include.
but this is good notice next time i will send the whole program

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Nuri Ismail · Accepted Answer · 2011-03-11T05:50:00

Solution 2

Please see this[^] and this[^] question from comp.lang.c[^].
The answers to these two questions contain all you need. :)

BTW: Your question is tagged as C++ not C. Above links will solve the problem in your C - style code.
If you want to change your code to C++ - style, then you can replace your two dimensional integer array with
std::vector< std::vector<int> > (see std::vector[^]) and pass this vector by reference to your function. :)

Posted 11-Mar-11 5:50am

Nuri Ismail

Updated 11-Mar-11 6:02am

v2

Comments

Sergey Alexandrovich Kryukov 11-Mar-11 21:43pm

Agree with you, my 5.
--SA

Nuri Ismail 12-Mar-11 11:23am

Thank you very much! :)

Espen Harlinn 13-Mar-11 5:22am

Nice reply, my 5 :)

Nuri Ismail 14-Mar-11 6:18am

Thanks! :)

Hans Dietrich · Accepted Answer · 2011-03-11T05:58:00

Solution 3

Your function should be like this:

void fun(int x[][6])
{
}

and you would call it like this:

int x[5][6];
fun(x);

Posted 11-Mar-11 5:58am

Hans Dietrich

Comments

Espen Harlinn 13-Mar-11 5:26am

my 5

Espen Harlinn · Accepted Answer · 2011-03-12T23:30:00

Solution 4

Oddly enough:

C++

int _tmain(int argc, _TCHAR* argv[])
{
  // argv points to an array of c style strings.
  // a c style string is a character array where the 
  // last character is set to '\x0'.

  // You had the required declaration for 2 dimensional arrays 
  // right in front of you all the time.
}

Regards
Espen Harlinn

Posted 12-Mar-11 23:30pm

Espen Harlinn

Comments

Sergey Alexandrovich Kryukov 13-Mar-11 15:20pm

My 5, in connection to the new Question by OP.
--SA

Espen Harlinn 13-Mar-11 15:30pm

Thank you, SAKryukov!