Reading a file in a form, and load to textbox in another form

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Hello,

I have 2 window forms, form1 and form 2. Form1 had a button(btnRead) that will read a file. How can I load the file that reading from button in form1 and load to textbox in form2.

Please help

C#

private void btnRead_Click(object sender, EventArgs e)
{
StreamReader streamRdr = new StreamReader(fileName);
textbox1.text = streamRdr.ReadToEnd();
streamRdr.Close();
}

The above code will read the file and display content in textbox in form1. How I can load to textbox in form2.

thanks,

Posted 10-Apr-12 6:18am

chaupha

Updated 10-Apr-12 8:31am

Nelek

v2

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Nelek 10-Apr-12 14:31pm

Edit: Fixed Tags

2 solutions

Solution 2

Simple Way:

1)go to:
Project->Project Properties->Settings
and add a new string(filename for example)

2)When Opening File you need code:

C#

Properties.Settings.Default.filename = filename;

3)On your second form add a timer and a code(in timer):

C#

if(Properties.Settings.Default.filename != "")
{
textBox1.Text = File.ReadAllLines(Properties.Settings.Default.fileName);
Properties.Settings.Default.filename = "";
}

Dont forget to enable added timer

Posted 10-Apr-12 10:25am

mmm3743

Updated 10-Apr-12 10:28am

v2

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OriginalGriff · Accepted Answer · 2012-04-10T06:31:00

You can do the reading a lot simpler:

C#

string s = File.ReadAllText(fileName);

Or

string[] lines = File.ReadAllLines(fileName);

The later is useful when you load a multiline TextBox:

C#

myTextBox.Lines = lines;

How to move the text to the second form (call it frmTwo):
In frmTwo, create a property:

C#

public string Text
    {
    get { return myTextBox.Text; }
    set { myTextBox.Text = value; }
    }

Or

C#

public string[] Lines
    {
    get { return myTextBox.Lines; }
    set { myTextBox.Lines = value; }
   }

In your first form, create an instance of the second form, set the data, and show it:

C#

frmTwo f = new frmTwo();
f.Text = File.ReadAllText(fileName);
f.ShowDialog();

Or

C#

frmTwo f = new frmTwo();
f.Lines = File.ReadAllLines(fileName);
f.ShowDialog();

You can use f.Show instead of f.ShowDialog