How to make Horizontal SpinnerList

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Hello friends,

I am using SpinnerList in my applicaiton and by default it has a vertical layout. But I have a requirement of Horizontal SpinnerList.

I tried rotation but that was not enough.

XML

<s:titleContent>
   <s:SpinnerListContainer direction="ltr"  autoLayout="true">
       <s:SpinnerList id="titleSpinner" textAlign="center" >
           <s:ArrayList>
              <fx:String>First</fx:String>
              <fx:String>Second</fx:String>
              <fx:String>Third</fx:String>
              <fx:String>Fourth</fx:String>
              <fx:String>Fifth</fx:String>
           </s:ArrayList>
       </s:SpinnerList>
   </s:SpinnerListContainer>
 </s:titleContent>

Please guide me

Posted 25-May-12 21:28pm

Manish Kumar Namdev

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Manish Kumar Namdev · Accepted Answer · 2012-05-27T20:43:00

Hello I found the solution. There no horizontal Spinner List. Therefore need to make a control.

XML

<s:Scroller id="scrllr"
                    focusEnabled="false"
                    hasFocusableChildren="true"
                    width="100%">
            <s:HGroup id="hg" gap="20"
                      paddingTop="5" paddingRight="5" paddingBottom="5" paddingLeft="5">
                <s:Label text="First" color="White"
                     focusIn="textinput_focusInHandler(event)"/>
                <s:Label text="Second" color="White"
                     focusIn="textinput_focusInHandler(event)" />
                <s:Label text="Third" color="White"
                     focusIn="textinput_focusInHandler(event)" />
                <s:Label text="Fourth" color="White"
                     focusIn="textinput_focusInHandler(event)" />
                <s:Label text="Fifth" color="White"
                     focusIn="textinput_focusInHandler(event)" />
                <s:Label text="Sixth" color="White"
                     focusIn="textinput_focusInHandler(event)" />
            </s:HGroup>
        </s:Scroller>

C#

protected function textinput_focusInHandler(evt:FocusEvent):void
            {
                var idx:int = hg.getElementIndex(evt.target as IVisualElement);
                var lay:HorizontalLayout =  hg.layout as HorizontalLayout;
                if(lay.fractionOfElementInView(idx)<1)
                {
                    lay.horizontalScrollPosition +=lay.getScrollPositionDeltaToElement(idx).y;
                }
            }