How to make row to column in SQL server

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SQL-Server-2008R2

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I have a table it contains value like

create table tableName (
dattime datetime, id int)

insert into tableName (dattime,id) values ('2019-05-07 07:15:000',1)
insert into tableName (dattime,id) values ('2019-05-07 13:50:000',1)
insert into tableName (dattime,id) values ('2019-05-07 07:15:000',2)
insert into tableName (dattime,id) values ('2019-05-07 13:50:000',2)

dattime                 | id
2019-05-07 07:15:00.000	| 1
2019-05-07 13:50:00.000	| 1
2019-05-07 07:15:00.000	| 2
2019-05-07 13:50:00.000	| 2

My Question is how to make this value as

id  |   col1              | col2
1   |   2019-05-07 07:15  | 2019-05-07 13:50
2   |   2019-05-07 07:15  | 2019-05-07 13:50

Please help!.....

What I have tried:

SELECT id, dattime FROM   
(SELECT id, dattime  FROM tableName )col1
PIVOT  (  
max(id) FOR dattime IN (dattime)) AS col2

Posted 6-May-19 23:14pm

nityanand NCR

Updated 6-May-19 23:48pm

v2

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Jörgen Andersson 7-May-19 5:30am

There is nothing identifying what should become Col1 and Col2.
And how would you handle the case where there are three rows for an ID?

2 solutions

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OriginalGriff · Accepted Answer · 2019-05-06T23:48:00

Solution 3

The simplest way is just to use GROUP BY:

SQL

SELECT ID, MIN(Dattime) AS Col1, MAX(Dattime) As Col2
FROM tableName 
GROUP BY ID

Posted 6-May-19 23:48pm

OriginalGriff

Comments

nityanand NCR 7-May-19 6:03am

5

Aravindba 7-May-19 6:17am

5+,

Aravindba · Accepted Answer · 2019-05-06T23:43:00

Hi
I think u need to get data in code like u mention above may be for report or chart , better declare data-table and use query to retrieve one by one and bind value dynamically in that data-table by programming code.

use this query to take id only

select id  from tablename group by id

, then loop with result,
e:g id '1 and 2 u will get 2 result each,
so first value bind in col 1 and 2 value bind in col 2 , same like for id - 2
first value bind in col 1 and 2 value bind in col 2

Regards,
Aravind