compare 2 number with bitwise operations

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hi everyone
I want to compare 2 number with them for example 2 and 3
and my program do this operations with bitwise operators.
i dont know how write this program
help pls
tanx

Posted 27-Sep-12 22:15pm

meysamp73

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Richard MacCutchan 28-Sep-12 4:17am

What do you mean by "with bitwise operators", what result are you trying to obtain?

meysamp73 28-Sep-12 4:29am

& The AND operator
| The OR operator
^ The XOR operator
~ The Ones Complement or Inversion operator
>> The Right Shift operator
<< The Left Shift operator.

for example we receive 2 , 3 numbers from input and show 3 is greater than 2

Richard MacCutchan 28-Sep-12 4:56am

Why not just use the math operators like > == etc.?

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CPallini · Answer 1 · 2012-09-27T23:18:00

For unsigned numbers you may simply right shift the numbers, until their leading bit (MSB) is different. e.g.
(I'm pretty sure there are more efficient ways, have a look, if you can at "Hacker's Delight"[^] book).

C

#include <stdlib.h>
#include <stdio.h>

int compare(unsigned int a, unsigned int b);
int main()
{
  unsigned int a, b;
  int i;

  for (i = 1; i<20; i++)
  {
    a =rand();
    b= rand();
    switch (compare(a,b))
    {
    case -1:
      printf("%u is smaller than %u\n", a, b);
      break;
    case 0:
      printf("%u is equal to %u\n", a, b);
      break;
      case 1:
      printf("%u is greater than %u\n", a, b);
      break;
    }
  }
  return 0;
}

int compare(unsigned int a, unsigned int b)
{
  unsigned int fb = 1 << (sizeof(a)*8-1);

  while ( !( (a ^ b) & fb))
  {
    a <<= 1;
    b <<= 1;
    if (!a && !b) return 0;
  }
  if ( a & fb)
    return 1;
  else
    return -1;
}

**JF2015** · Answer 2 · 2012-09-27T22:31:00

Solution 1

What about:

C++

int integer1 = 666;
int integer2 = 666;
int result = integer1 & integer2; //bitwise AND
if(result == integer1)
{
}

Posted 27-Sep-12 22:31pm

JF2015

Updated 27-Sep-12 22:32pm

v2