Conversion of CString to unsigned char

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Hi,

I want to convert the CString variable to unsigned char.
Can anyone help in this.

Here is my code,

C++

VARIANT varVal;
CString strValue = "1";
unsigned char* cVal = (unsigned char*) (LPCTSTR) strValue;
varVal.bVal = *cVal;

If I execute the above code the value is displaying as "49"(varVal.bVal), but i want to display as "1".

Any help in this?

Posted 14-Oct-12 19:00pm

Durga_Devi

Updated 14-Oct-12 19:23pm

v3

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Sergey Alexandrovich Kryukov 15-Oct-12 1:21am

It's not nice to post code which won't even compile. What's "unsigend". It's a shame; you need to use Paste from copied real code.
--SA

Durga_Devi 15-Oct-12 1:23am

thanx. will modify the syntax

Sergey Alexandrovich Kryukov 15-Oct-12 1:35am

You are very welcome. Let's see... much better now :-)
--SA

Sergey Alexandrovich Kryukov 15-Oct-12 1:37am

I just fixed my answer where I messed up the links before -- sorry for the inconvenience.
Now the answer is ready -- please see.
--SA

4 solutions

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Sergey Alexandrovich Kryukov · Answer 1 · 2012-10-14T19:14:00

First of all, you need to understand why you get 49. This is because this is the ASCII value of the character '1':
http://en.wikipedia.org/wiki/ASCII[^].

The whole idea of "conversion" is wrong and manifest the lack of your understanding how data is represented in principle. To get what you want, you need to do something which is not related to "conversion"; this is "parsing". One of the functions you can use is this:
http://www.cplusplus.com/reference/clibrary/cstdlib/atoi[^].

This function needs a null-terminated string (as a char * pointer), which only looks like a typecast, but in fact this is a casting operator:
http://msdn.microsoft.com/en-us/library/aa300569%28v=vs.60%29.aspx[^].

—SA

LaxmikantYadav · Answer 2 · 2012-10-14T19:23:00

Solution 3

CString strValue = "1";
unsigend char* cVal = (unsigned char *) strValue.GetBuffer(0);

Posted 14-Oct-12 19:23pm

LaxmikantYadav

Comments

Nikita Vedre 29-Jun-21 8:16am

It still give same error

Durga_Devi · Answer 3 · 2012-10-14T19:43:00

Solution 4

The above can be modified as,

C++

varVal.vt = VT_BSTR;
varVal.bstrVal = m_strValue.AllocSysString();
VariantChangeType(&varVal,&varVal,0,VT_UI1);

Now the varVal.bVal will have the value "1".

Posted 14-Oct-12 19:43pm

Durga_Devi

vaibhavbvp · Answer 4 · 2012-10-15T01:19:00

Solution 5

CString str = "sample";

char* c= str.getbuffer();
str.releasebuffer();

Posted 15-Oct-12 1:19am

vaibhavbvp