Display distinct date as columns

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SQL-Server-2008

Hi Experts,
i have a table in the following format

Date               Node  KPI1  KPI2  KPI3
2012-10-11         RNC1   2    5      10
2012-10-11         RNC2   3    5      12
2012-10-11         RNC3   2    6      10
2012-10-12         RNC1   9    1      16
2012-10-12         RNC2   6    2      10

I want to diplay it this way

Node  KPI    2012-10-11 2012-10-12
RNC1  KPI1   2           9
RNC1  KPI2   5           1
RNC1  KPI3   10         16
RNC2  KPI1   3           2

Please suggest how to do this in sql.

Thanx

Posted 17-Oct-12 21:04pm

Member 9524229

Updated 17-Oct-12 21:11pm

Mehdi Gholam

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Mukesh_Chauhan · Answer 1 · 2012-10-17T21:11:00

Your query will return unique DATES, as you've specified. If you want to get just unique MONTHS/YEARS, you should either modify you dates in a way, that each date becomes the first day of the month, or you should just go with some string representation like 'YYYY-MM'. Sorry, I can't write you an exact code how to do this, as I do not develop on mysql, but I think this should get you somewhere :)

SQL

SELECT DISTINCT YEAR(date_posted), MONTH(date_posted) FROM table

Mehdi Gholam · Answer 2 · 2012-10-17T21:12:00

Solution 2

This is a pivot, read the following : http://msdn.microsoft.com/en-us/library/ms177410%28v=sql.105%29.aspx[^]

Posted 17-Oct-12 21:12pm