Get numbers and words from characters

Question

4.00/5 (1 vote)

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C#

char[] charArray = new char[1000];
charArray = richTextBox1.Text.ToCharArray();
for (int i = 0; i < charArray.Length; i++)
{
    int c = Convert.ToInt32(charArray[i]);
    if(c>=48 && c<=57)
     listView1.Items.Add(charArray[i].ToString() + "-->number");

     else if (Char.IsLetter(charArray[i]))
      {
          int c1 = Convert.ToInt32(charArray[i]);
         if (c1 >= 65 && c1 <= 90 || c1 >= 97 && c1 <= 122)
         listView1.Items.Add(charArray[i].ToString() + "-->alphabet");
                                }
}

Got stack in a small problem.Try to find numbers and words from this loop.But what i do is..it prints as letter or digit for each character.But i want if i write 123.45 or write WORD in richtextbox it will show output as 123.45 is a number and WORD is a word in listview.but my loop prints as like as...
1-->number
2-->number
.
.
W-->alphabet
O-->alphabet
.
.
So how can i combine these characters as number or word?Is my checking criteria is wrong?

Posted 12-Nov-12 6:45am

ridoy

Updated 12-Nov-12 6:48am

v2

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4 solutions

Solution 1

Hi,

Try this:

C#

string[] parts = richTextBox1.Text.Split(' '); // split the text
foreach (string part in parts)
{
      double d = 0;
      if (double.TryParse(part,d)) // try to parse the current part to a number
      {
            listView1.Items.Add(part + "-->number"); // if you can parse, add part + "-->number" to the ListView
      }
      else
      {
            listView1.Items.Add(part + "-->word"); // if you can't parse, the current part is a word, add part + "-->word" to the ListView
      }          
}

Hope this helps.

Posted 12-Nov-12 6:57am

Thomas Daniels

Comments

ridoy 12-Nov-12 13:00pm

Thanks for your reply,but sorry i need to escape whitspace for what i can't check those characters by detecting whitespace.

Solution 3

You will need to store the chars in a variable then print them when you change to the other type. Below is an example. This example doesn't check for punctuation or white space though you could easily add that.

C#

private void ParseThis()
        {
            char[] charArray = new char[1000];
            charArray = richTextBox1.Text.ToCharArray();
            string number = string.Empty;
            string word = string.Empty;

            for (int i = 0; i < charArray.Length; i++)
            {
                int c = Convert.ToInt32(charArray[i]);
                if (c >= 48 && c <= 57)
                {
                    if (number.Length == 0)
                    {
                        if (word.Length > 0)
                            listView1.Items.Add(word + "-->alphabet");
                        word = string.Empty;
                    }
                    number += charArray[i].ToString();
                }

                else if (Char.IsLetter(charArray[i]))
                {
                    int c1 = Convert.ToInt32(charArray[i]);
                    if (c1 >= 65 && c1 <= 90 || c1 >= 97 && c1 <= 122)
                    {
                        if (word.Length == 0)
                        {
                            if (number.Length > 0)
                                listView1.Items.Add(number + "-->number");
                            number = string.Empty;
                        }

                        word += charArray[i].ToString();
                    }
                }
            }


            if (word.Length > 0)
                listView1.Items.Add(word + "-->alphabet");
            if (number.Length > 0)
                listView1.Items.Add(number + "-->number");

        }

Posted 12-Nov-12 7:13am

BC @ CV

Solution 2

If I understood correctly, if input is 123.45, it should say "NUMBER" else it should say "WORD".
If this is true, why dont you try double.TryParse ? and Int.TryParse?
It will be something like

C#

double value;
bool isNumber = double.TryParse(richTextBox1.Text,out value);
if(isNumber)
{
  listView1.Items.Add("NUMBER");
}
else
{
  listView1.Items.Add("WORD");
}

Hope that helps
Milind

Posted 12-Nov-12 7:13am

MT_

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ridoy · Accepted Answer · 2012-11-12T22:02:00

Thanks for response.I solve it using following code..

C#

 while(i<chararray.length)>
             {  
                while (Char.IsDigit(charArray[i]) || Char.IsLetter(charArray[i]))
                 {
                      word = word + charArray[i];
                      i++;
                 }
                         
                      double num;

                      if (double.TryParse(word, out num))
                      {
                           if (charArray[i].ToString() == ".")
                           {
                                word += charArray[i];
                                i++;
                                while (Char.IsDigit(charArray[i]))
                                {
                                    word += charArray[i];
                                    i++;
                                }
                            }
                            listView1.Items.Add(word +"-->number");
                       }
                       else
                       {
                           listView1.Items.Add(word +"--->word");
                       }
                       word = "";
}