[Ljava.lang.string; @52e922 is what getsprinted should print array contents

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1.00/5 (1 vote)

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public class JavaArrays 
{                        
         public static void main(String[] args) 
         {
                        String[] Words = new String[4]; 
                        Words[0] = "Android";
                        Words[1] = "Java";
                        Words[2] = "CSS";
                        Words[3] = "JavaScript";   

                        for(String word : Words)
                        {
                        System.out.print(Words);                                               
                        System.out.println();
                        } 
}

the result is ;
[Ljava.lang.String;@52e922
[Ljava.lang.String;@52e922
[Ljava.lang.String;@52e922
[Ljava.lang.String;@52e922

should
Android
Java
CSS
JavaScript

What I have tried:

changed code several times java docs

Posted 25-Aug-19 2:00am

four systems

Updated 25-Aug-19 2:09am

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Afzaal Ahmad Zeeshan · Accepted Answer · 2019-08-25T02:09:00

The reason you are getting 4 outputs is because you have 4 elements in the array,

Java

for(String word : Words)

But you are printing the array itself, not the String element. Thus, Java is unable to print the array rather outputs the address where that object is being stored in the memory. You can fix that by changing the line of code that prints the words,

Java

for(String word : Words)
{
    System.out.println(word); 
}

Like this, now the output would be the words in the array, not the array itself.

Complete code for this would be,

Java

public class JavaArrays {

     public static void main(String []args) {
        String[] Words = new String[4]; 
        Words[0] = "Android";
        Words[1] = "Java";
        Words[2] = "CSS";
        Words[3] = "JavaScript";   

        for(String word : Words) {
            System.out.println(word); 
        } 
     }
}

You can try this sample in your own IDE.