- an integer
`i`

is divisible by`8`

if`(i%8)!=0`

- you have the string representation of the number, it is not a daunting task to find there is a
`'0'`

character in such a string

14,693,384 members

See more:

Find the sum of n digit pallindromic numbers which are divisible by 8 and contains no zero in their decimal representation.

**What I have tried:**

```
import java.util.*;
class GFG
{
static boolean isPalindrome(String s)
{
int left = 0, right = s.length() - 1;
while (left <= right)
{
if (s.charAt(left) != s.charAt(right))
{
return false;
}
left++;
right--;
}
return true;
}
static long getSum(int n)
{
int start = (int) Math.pow(10, n - 1);
int end = (int) (Math.pow(10, n) - 1);
long sum = 0;
for (int i = start; i <= end; i++)
{
String s = String.valueOf(i);
// Append
if (isPalindrome(s))
{
sum += i;
}
}
return sum;
}
public static void main(String[] args)
{
int n = 1;
long ans = getSum(n);
System.out.print(ans);
}
}
```

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