Java Application Start Path

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Hello everyone,

Finally, I finished my graduation project. I am putting some extra facilities. However, ı faced with a problem. There was a code line in .net while reading some folders or files. when we wrote Application.StartupPath... the project directs the user "proje\bin\debug folder. In this manner, I want to use the same facility. I have a resources.rar folder. When the user clicked on the download the source link this should be downloaded. However, I am using my own path C:Users/Emre/etc...

Is there any way to solve this?

Thank you.

Posted 17-Jan-13 12:46pm

FoxRoot

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Sergey Alexandrovich Kryukov 17-Jan-13 19:05pm

Not quite clear. Do you need similar functionality for Java, or it is still somehow related to .NET?
—SA

FoxRoot 18-Jan-13 2:09am

I am sorry, I am using the file path as C:Users/Emre/....
But, when we move the project to another pc, it wont work. There was a code in .net we use Application.StartupPath+"\resources.rar" and this works any pc. I am asking is there a code doing sama things for java?

2 solutions

Solution 2

For the record: I believe I answered here: Raising the portability of program[^].

—SA

Posted 18-Jan-13 15:31pm

Sergey Alexandrovich Kryukov

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TorstenH. · Accepted Answer · 2013-01-17T19:54:00

Solution 1

Yes. You need to use relative paths, not absolute.
There should be a package ResourceBundle for doing so. Please check that.

If you are linking in from another destination (some .net app), you should use a property for configuring a decent path.

Posted 17-Jan-13 19:54pm

TorstenH.

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FoxRoot 18-Jan-13 2:09am

I am sorry TorstenH. Still couldn't find anything.

TorstenH. 18-Jan-13 5:58am

yeah - google is wired. I like to use "feel lucky" in those cases. Works quite well:

ResourceBundle in Java 6SE

FoxRoot 18-Jan-13 7:43am

Thank you TorstenH. I solved with this link.