How to decode the string after the null character?

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C

main()
{
char str[20] = "SINGLE\0*DOUBLE*";
printf("8th character is %c\n", str[8]);
}

Hi, actually i need to decode the string after the null character but i got upto the null character string(only accessible upto SINGLE). i do not know how to solve the issue, please help it.

What I have tried:

used strcpy, snprintf for initializing the variable

Posted 12-Jul-22 20:38pm

mathi1234

Updated 12-Jul-22 22:11pm

CPallini

v2

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KarstenK 13-Jul-22 4:16am

Because you have an 0 termination that data isnt a string per definition. You are jiggling around with the chance of nasty bugs.

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CPallini · Answer 1 · 2022-07-12T21:48:00

In C you have to use a function, like memchr that doesn't consider '\0' character the end-of-the-string. Try, for instance

C

#include <stdio.h>
#include <string.h>
int main()
{
  char str[] = "SINGLE\0*DOUBLE*";
  char * p = str;

  for(;;)
  {
    size_t remain = sizeof(str) - (p - str + 1);
    if ( ! remain )
      break;
    printf("%s\n", p);
    p = memchr(p, 0, remain);
    if ( ! p )
      break;
    ++p;
  }

  return 0;
}

Patrice T · Answer 2 · 2022-07-12T22:11:00

Quote:
How to decode the string after the null character?

By C definition, a string is a zero terminates array of chars.
This means that all common C string functions will stop at the zero.

Run this code:

C++

void main() {
    char str[20] = "SINGLE\0*DOUBLE*";
    printf("8th character is %c\n", str[8]);
    for (int i=0; i<20; i++) {
        printf("value:%i char:'%c' string: '%s'\n", (int)str[i], str[i], &str[i]);
    }
}

Richard MacCutchan · Answer 3 · 2022-07-12T21:58:00

If you are certain that there are only two words then it is fairly simple:

C++

char str[20] = "SINGLE\0*DOUBLE*";
char* first = str;
char* second = first + strlen(first) + 1;

printf("First: %s, Second: %s\n", first, second);

If you expect multiple entries then it is a good idea to terminate the final entry with an extra null character:

C++

char list[] = "first\0second\0third\0\0"

Ruyter64 · Answer 4 · 2022-07-12T21:30:00

Solution 1

Hi,
may be you can do a replace code than delete the null character before your printf

for(int i = 0; i <= strlen(str); i++)
  	{
  		if(str[i] == "\O")  
		{
  			str[i] = "";
 		}
	}

Posted 12-Jul-22 21:30pm

Ruyter64

Comments

CPallini 13-Jul-22 4:38am

How do you hope to find '\0' in the 0..strlen(str) range?

Ruyter64 13-Jul-22 4:55am

you're right.
may be better to use strrchr() to search a special character and the with the position found replace it by other character.

CPallini 13-Jul-22 5:02am

Nope, as correctly stated by Patrice: "This means that all common C string functions will stop at the zero.". You have to use a different kind of function (like, for instance, the one I used: memchr),

How to decode the string after the null character?

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