http://en.wikipedia.org/wiki/Rounding[^]

To do this use ceil():

http://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#ceil(double)[^]

so:

JavaScript

p1 = Math.ceil(sum1 * 0.12);

See more:

I've used a fuction on key up event in the script below.

All is working fine but I want to round off the value 'p1' as If value is in between 5.000001 - 5.999999 the result should be 6.

Thanks in advance.

All is working fine but I want to round off the value 'p1' as If value is in between 5.000001 - 5.999999 the result should be 6.

Thanks in advance.

JavaScript

$(function () { var textBox1 = $('input:text[id$=FreightCharges]').keyup(foo); var textBox2 = $('input:text[id$=FuelSurcharge]').keyup(foo); var textBox3 = $('input:text[id$=FOV]').keyup(foo); function foo() { var value1 = textBox1.val(); var value2 = textBox2.val(); var value3 = textBox3.val(); var p1 = per(value1, value2, value3); $('input:text[id$=ServiceTax]').val(p1); } function per() { var sum1 = 0, p1 = 0; for (var i = 0, j = arguments.length; i < j; i++) { if (IsNumeric(arguments[i])) { sum1 += parseInt(arguments[i]); p1 = parseInt(sum1 * 12) / 100; } } return p1; } function IsNumeric(input) { return (input - 0) == input && input.length > 0; } });

Comments

There are a number of types of rounding. You wish to "always round up to an integer" not "round off" which implies rounding down.

http://en.wikipedia.org/wiki/Rounding[^]

To do this use ceil():

http://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#ceil(double)[^]

so:

http://en.wikipedia.org/wiki/Rounding[^]

To do this use ceil():

http://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#ceil(double)[^]

so:

JavaScript

p1 = Math.ceil(sum1 * 0.12);

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v4

Comments

5+

arunsiddhu1992
13-May-15 4:24am

I got It.

Thanks.:)

Thanks.:)

Rounded percentage in JS:

JavaScript

function RoundedPct(quantity, percent) { return Math.ceil(quantity * percent / 100); }

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v3

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[no name]
11-May-15 6:28am

Round rounds to nearest integer. Thus:

5.000001 gives 5

5.999999 gives 6

Not what the questioner asked for.

5.000001 gives 5

5.999999 gives 6

Not what the questioner asked for.

right you are! I missed that one due to the title ... fixed the title, and the A

arunsiddhu1992
13-May-15 4:23am

Thanks I've got the solution.

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p1 = parseInt(sum1 * 12) / 100;

to

p1 = Math.round(sum1*0.12);//move 0.12 in a variable

or

p1 = Math.ceil(sum1*0.12);//move 0.12 in a variableor

or

p1 = Math.floor(sum1*0.12);//move 0.12 in a variable