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I've used a fuction on key up event in the script below.
All is working fine but I want to round off the value 'p1' as If value is in between 5.000001 - 5.999999 the result should be 6.

Thanks in advance.

JavaScript
$(function () {
var textBox1 = $('input:text[id$=FreightCharges]').keyup(foo);
var textBox2 = $('input:text[id$=FuelSurcharge]').keyup(foo);
var textBox3 = $('input:text[id$=FOV]').keyup(foo);

function foo() {
var value1 = textBox1.val();
var value2 = textBox2.val();
var value3 = textBox3.val(); 
var p1 = per(value1, value2, value3); 
$('input:text[id$=ServiceTax]').val(p1);
}
function per() {
var sum1 = 0, p1 = 0;
for (var i = 0, j = arguments.length; i < j; i++) {
if (IsNumeric(arguments[i])) {
sum1 += parseInt(arguments[i]);
p1 = parseInt(sum1 * 12) / 100;
}
}
return p1;
}
function IsNumeric(input) {
return (input - 0) == input && input.length > 0;
}

});
Posted
Updated 11-May-15 1:20am
v3
Comments
Mohibur Rashid 11-May-15 4:53am    
change this line
p1 = parseInt(sum1 * 12) / 100;
to
p1 = Math.round(sum1*0.12);//move 0.12 in a variable
or
p1 = Math.ceil(sum1*0.12);//move 0.12 in a variableor
or
p1 = Math.floor(sum1*0.12);//move 0.12 in a variable

There are a number of types of rounding. You wish to "always round up to an integer" not "round off" which implies rounding down.
http://en.wikipedia.org/wiki/Rounding[^]

To do this use ceil():

http://docs.oracle.com/javase/7/docs/api/java/lang/Math.html#ceil(double)[^]


so:

JavaScript
p1 = Math.ceil(sum1 * 0.12);
 
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v4
Comments
Joezer BH 11-May-15 7:27am    
5+
arunsiddhu1992 13-May-15 4:24am    
I got It.
Thanks.:)
Rounded percentage in JS:
JavaScript
function RoundedPct(quantity, percent)
{
    return Math.ceil(quantity * percent / 100);
}
 
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v3
Comments
[no name] 11-May-15 6:28am    
Round rounds to nearest integer. Thus:
5.000001 gives 5
5.999999 gives 6

Not what the questioner asked for.
Joezer BH 11-May-15 7:19am    
right you are! I missed that one due to the title ... fixed the title, and the A
arunsiddhu1992 13-May-15 4:23am    
Thanks I've got the solution.

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