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Posted 19 Aug 2006

# Create Postfix from infix experssion.

, 19 Aug 2006
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this article create postfix experssion from an infix experssion.
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## Introduction

Ali reza zareian.

This is a simple program that creates postfix expression from an infix expression. What is an infix expression?<?xml:namespace prefix = o ns = "urn:schemas-microsoft-com:office:office" /><o:p>

<o:p>

(a+b)/d is a simple one. The infix expression is regular for mathematic. it means when u want to calculate this u must<o:p>

Add a with b at the first time then divided with d.<o:p>

If  we change this expression to postfix. We have this one ab+d/.<o:p>

What is the useful of postfix?<o:p>

At first we don't need parantes.Second we can write a program to calculate this expression easier than infix expression.<o:p>

<o:p>

What is this program?<o:p>

This programe use a simple algoritm to change infix to postfix.Just sees the example<o:p>

Before I should say I use stack in this program.<o:p>

<o:p>

Infix Program =(a+b)/d  <o:p>

<o:p>

<o:p>

Input     Stack        output<o:p>

(             (<o:p>

a            (                     a<o:p>

+           (+                   a<o:p>

b           (+                   ab<o:p>

)                                  ab+<o:p>

/            /                     ab+<o:p>

d                                 ab+d<o:p>

No         empty           ab+d/<o:p>

<o:p>

<o:p>

Main method of this program!?

1)      private int isOperand(char  chrTemp);

2)      private int isOperator(char chrTemp);

3)      public string createPrifex();

<o:p>

<o:p>

1) isOperand check character if they are in this set.{'*','/','+','-','^','('}

If true we add this character to stack.

<o:p>

2)isOperator check character if they are in this set.{'*','/','+','-','^'}

This  method check the  stack  and  pop all the operator except '('.

<o:p>

3)createPrifix method create postfix from infix use isOperand and isOperator.

<o:p>

PesoCode

For (the first infix character ) to  last character

{

If  (is operand)   add to stack

Elae

If  (it is ')' )   pop  stack and send it to output

Else send other character to output

}

<o:p>

}

<o:p>

<o:p>

<o:p>

<o:p>

<o:p>

<o:p>

## License

This article has no explicit license attached to it but may contain usage terms in the article text or the download files themselves. If in doubt please contact the author via the discussion board below.

A list of licenses authors might use can be found here

## About the Author

 Software Developer Iran (Islamic Republic of)
Where is the truth?

## Comments and Discussions

 First Prev Next
 M_k m _k16-Oct-13 7:01 m _k 16-Oct-13 7:01
 My vote of 1 Mohamad K Ayash3-Oct-09 11:30 Mohamad K Ayash 3-Oct-09 11:30
 Very Messy. Lots of typos. Weak content for a very classical problem in a 2nd course in programming.
 Incorrect Solution naeem_libra8-Dec-08 19:50 naeem_libra 8-Dec-08 19:50
 Re: Incorrect Solution ali_reza_zareian21-Jan-09 7:24 ali_reza_zareian 21-Jan-09 7:24
 help me i am not getting proper out put for infix to post evaln(main problem in evaluvation) karthikragunath8712-Aug-08 19:05 karthikragunath87 12-Aug-08 19:05
 Better method PIEBALDconsult11-Jun-08 17:26 PIEBALDconsult 11-Jun-08 17:26
 WATCH OUT! This solution is wrong!! Member 451662817-Mar-08 13:14 Member 4516628 17-Mar-08 13:14
 Re: WATCH OUT! This solution is wrong!! ali_reza_zareian18-Mar-08 9:14 ali_reza_zareian 18-Mar-08 9:14
 Re: WATCH OUT! This solution is wrong!! PKokkula27-Jul-09 2:16 PKokkula 27-Jul-09 2:16
 plz help me behruoz guozali asl8-Dec-07 7:01 behruoz guozali asl 8-Dec-07 7:01
 Re: plz help me ali_reza_zareian21-Jan-09 7:07 ali_reza_zareian 21-Jan-09 7:07
 precedence logic is missing SoftwareCat17-May-07 5:11 SoftwareCat 17-May-07 5:11
 Good? azam's25-Feb-07 19:03 azam's 25-Feb-07 19:03
 Don't meant to complain but... Herbert Sauro21-Aug-06 19:41 Herbert Sauro 21-Aug-06 19:41
 Last Visit: 31-Dec-99 18:00     Last Update: 22-Jun-17 14:49 Refresh 1

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