It appeared as though the Delauney method only worked for polygons that were contained within the convex hull of the set of polygons. It appears as the method shown here works on concave polygons as well.

A more little explanation about my article. In order to tesselate the polygon i use this tecnique:
First compute the normal of polygon (i use the newell method see Graphic Gems..)
For each sequence of three vertex ( i, j, k ) in the polygon compute the vector area (alias normal of triangle).
If the normal go in the opposite direction of polygon normal the triangle is 'concave' and go ahead.
If the area il 0.0 the point j is alligned from i to k and eliminated from the list of vertex.
If the normal of triangle is in the same direction of polygon normal the triangle is convex. In the last case check if any other point is inside the triangle (the IsPointInside function). This function test if the point is on solid angle ik ^ jk. if this is true compute distance of intersection k->point to line ij and test distance. If all is good emit triangle, remove vertex j from list and go to the next triplet....
The reason for wich i posted this article is that i don't find this tecnique in any book or article and ave a doubt about the mathematical basic of my algoritm In other words is true that it work in any case ? (my experience ask yes but is very far from a theorem...)
The Delauney algortim work fine but is 'computational' more expensive than my algortim (using my Delauney implementation) for this reason i try this way. At the end my apologize fro my poor english but my sincerly idea is to contribute to codeproject and suggest a way to resolv a problem that i found. Thanks pepito.

Last Visit: 31-Dec-99 18:00 Last Update: 18-Jun-18 4:11