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Should be ok, provided you want to append every time you call this function. Else you will probably have to clear the GridControl first.
The good thing about pessimism is, that you are always either right or pleasently surprised.
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can you gives some basics about GridControl?
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you can also write like this..
//this line write before for loop
//with this line grid(dataGridView1) create line as per dataTable(t)
dataGridView1.RowCount=t.Rows.Count
for (int i = 0; i < t.Rows.Count; i++)
{
dataGridView1.Rows[i].Cells["Column1"].Value = t.Rows[0]["Address"].ToString();
}
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using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Runtime;
using System.Data;
using System.Drawing;
using System.Text;
using System.Windows.Forms;
using System.Runtime.Remoting;
using System.Runtime.Remoting.Channels;
using System.Runtime.Remoting.Channels.Tcp;
using Project1;
namespace Server
{
public partial class Form1 : Form
{
private TcpChannel tcpchannel = null;
private int port = 8998;
private Type type;
private WellKnownObjectMode wellknownobj;
private string objURL;
public Form1()
{
InitializeComponent();
}
private void Form1_Load(object sender, EventArgs e)
{
}
private void btnKhoi_Click(object sender, EventArgs e)
{
try {
btnTat.PerformClick();
port = Int32.Parse(txtPort.Text);
tcpchannel = new TcpChannel(port);
ChannelServices.RegisterChannel(tcpchannel,false);
type = typeof(Proxy);
objURL ="Prime_URL";
if(rdb_sTon.Checked==true)
wellknownobj = WellKnownObjectMode.Singleton;
else
wellknownobj = WellKnownObjectMode.SingleCall;
RemotingConfiguration.GetRegisteredActivatedServiceTypes(type,objURL,wellknownobj);//Error this line
txtTrThai.Text="Khoi dong server tai Port"+port.ToString()+"luc"+ DateTime.Now.ToString();
}catch(Exception ex){
MessageBox.Show("Loi", ex.Message);
}
}
private void btnTat_Click(object sender, EventArgs e)
{
if (ChannelServices.GetChannel("tcp") != null) {
ChannelServices.UnregisterChannel(tcpchannel);
txtTrThai.Text = "tat server tai port" + port.ToString() + "luc" + DateTime.Now.ToString();
}
}
}
}
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It's telling you that the method doesn't take three parameters. In fact, it doesn't take any parameters - you can find this out by looking up the definition[^] on MSDN. Also, your call here is completely useless because you don't assign it back to anything.
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I am doing a project in which i am trying to read the data that is being sent from my microcontroller to the PC through serial port.
I am ok with the serial part (i guess)...
I was thinking of making it like, first when i run the program a gui would pop up asking user to select the COM port and other details like handshake, parity, baud rate, etc.
And after setting all that when the user presses the START button the current form should close and another form should pop up showing the data being read from the port continously.
Is that possible to create multiple forms ????
If possible please help me in doing so....
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alfie.max15 wrote: Is that possible to create multiple forms
Yes of course it is possible, use winforms or WPF for the UI.
Help you - Ok!
Do some research and decide on a platform, then get a book on that platform, read the book and do the examples.
When you have completed that start your application, when you run across a specific problem come back and we may be able to help you.
Never underestimate the power of human stupidity
RAH
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Thanx... I did that...
Now what i specifically want is that when i press the button the form2 should pop up but at the same time the form1 should close.
i tried...
In form1
private void Start_Click (object sender, EventArgs e)
{
secondForm.Show();
this.Close ();
}
but what happened was that the form2 will open and both form 1 and form2 get closed.
i thought only form1 will get close as i had called this from form1
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If Form1 is the main form, the application will end on closing it. You could create 2 additional forms, make the main form invisible and start the second form (for taking the parameters) in the load event of the main form. Also you should open it with ShowDialog() to create a modal form.
On pressing the button confirm you set the DialogResult to something specific, so you get this value as return value from ShowDialog() after closing your parameter form. Then you can open the third form showing the data.
Another approach would be to transfer the logic of opening the second dialog to the program class, opening the second form if the main form was closed using confirm and exit tha pplication only if the second form is closed or the main form is closed in another way than pressing confirm.
The good thing about pessimism is, that you are always either right or pleasently surprised.
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I vote for your "2nd form" becoming the main form. It's what you actually want to see anyway.
The main form can create and show what now is you "1st form". But it essentially is just a dialog to set up some properties. So make it just a dialogue that is started by your main form.
Additional benefit: Later, you can implement a menu, button or whatever control so user can open a connection properties dialogue again, with the same logic you already have (in case user entered wrong parameter, or another controller on another port, or...).
Ciao,
luker
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using System;
using System.Collections.Generic;
using System.Text;
namespace ClassLibrary1
{
public class Khachhang:MarshalByRefObject
{
private string tennguoitruoc;
private int songuoi;
public Khachhang (){
tennguoitruoc = "";
songuoi = 0;
Console.WriteLine("Doi tuong duoc khoi tao");
}
public string Laythongtin(string ten){
Console.WriteLine("Doi tuong goi ham");
string thongdiep;
if (tennguoitruoc.Length == 0)
thongdiep = "Chao" + ten + "Ban la nguoi dau tien";
else
"Chao," + ten + ".Co" + songuoi.ToString() +
"nguoitruocban,va" + tennguoitruoc + "la nguoi dung truocban";//Error at this line:tennguoitruoc.
:
songuoi++;
tennguoitruoc = ten;
return thongdiep;
}
}
}
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Member 10326659 wrote:
"Chao," + ten + ".Co" + songuoi.ToString()
+
"nguoitruocban,va" + tennguoitruoc + "la
nguoi dung truocban";//Error at this line:tennguoitruoc.
That's an expression, but you're not assigning it to anything.
Did you mean to say:
thongdiep = "Chao," + ten ........
The difficult we do right away...
...the impossible takes slightly longer.
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Beat me by the speed of my DSL 
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Should be:
thongdiep = "Chao," + ten + ".Co" + songuoi.ToString() +
"nguoitruocban,va" + tennguoitruoc + "la nguoi dung truocban";
Notice the assignment? thongdiep = at the beginning? its missing in your statement. You can't add strings together without putting them somewhere when you are done, thats what the compiler is trying to tell you.
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Thanks you very much but i can not compile it.Can you help me to fix that code.Thanks
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What error do you get when you try to compile?
Veni, vidi, abiit domum
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Hello,
I want to write a c#-application which is able to transfer zipped files (tar.gz) to Linux-Server using SSH. A SH-Script on this server has to evaluate the data and then give the answer back to the windows client via stdOut.
The command line in the terminal in Linux to do this looks like this:
cat dummy.tar.gz | ssh root@192.168.13.7 /bin/remoteEvaluation.sh params
As I am understanding the tar-file first gets loaded into the StdOutput of the client and then it gets piped to be the StandardInput for the connection to the server via SSH. In Evaluation.sh the StandardInput gets evaluated and then the results gets back to the client via stdoutput of ssh.
I have just found a lib (SSH.Net) and was able to successfully connect to the server via ssh and to be able to execute some commands on this server:
PrivateKeyFile key = new PrivateKeyFile(@"D:\Path\id_rsa");
SshClient sshClient = new SshClient("192.168.13.7", "usr", new PrivateKeyFile[] { key });
sshClient.Connect();
SshCommand cmd = sshClient.CreateCommand("ls -ltr");
cmd.Execute();
Console.WriteLine(cmd.Result);
sshClient.Disconnect();
It's a pity that I don't know how to get zipped tar-file via stdIn into the server, so that the evaluation.sh has some input to evaluate.
I recognized that the SSH.Net-Lib also provides a function named "CreateShell", which looks like follows:
public Shell CreateShell(Stream input, Stream output, Stream extendedOutput, string terminalName, uint columns, uint rows, uint width, uint height, IDictionary<TerminalModes, uint> terminalModes, int bufferSize)
Furthermoe there is a function to create a Shellstream:
public ShellStream CreateShellStream(string terminalName, uint columns, uint rows, uint width, uint height, int bufferSize)
Maybe I can use these functions to get the binary stream of the zipped file to the server.
If someone could give me a hint, how I can solve this problem I'd be very happy.
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I Googled it and found this.[^]
It describes problem, but my table has a PK.
When I try to reference to table in code, it's not there.
Anyone know what's wrong?
If it's not broken, fix it until it is
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Could be any one of a million things. Please try and be a bit more specific about what you are doing and what results you see.
Veni, vidi, abiit domum
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There's nothing else to tell.
I drag a table from Server Explorer into the DBML Designer but it doesn't show in code.
If it's not broken, fix it until it is
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The difficult we do right away...
...the impossible takes slightly longer.
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Any way the wind blows
Nothing really matters to me
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to me.
Mama, just killed a man
Put a gun against his head
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Pulled my trigger
Now he's dead
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