
I live in an old(*), brokendown house. Does that count?
(*) Front half of the house, built in 1872. In 1892, moved to its current location ½ a mile away. 1920's, built on the rear portion of the house, including dining room, kitchen, and laundry. Has spent all those years settling at various rates on/around the supports in the basement. No redeeming architectural features whatsoever.
Software Zen: delete this;





Yes will give you a waiver.
Everyone has a photographic memory; some just don't have film. Steven Wright





Don't waive too hard please, something might fall off and hurt someone.
Software Zen: delete this;





I'm old, all the pieces that are going to fall off have a long time ago.
Everyone has a photographic memory; some just don't have film. Steven Wright





Your questions about father newbie are always welcome, and also feel free to ask about father Christmas






Cordelias House wrote: and asking some father newbie questions to start with
Welcome, but I am NOT your father!
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Learning to code with python is like learning to swim with those little arm floaties. It gives you undeserved confidence and will eventually drown you.  DangerBunny
Artificial intelligence is the only remedy for natural stupidity.  CDP1802





Last week while working on a new report, I needed a formula that would calculate a shortage/overage for a variable and had the equation worked out as follows:
a/(a+b) = c/d where I was solving for the variable a.
It's been 30 years since I had algebra, and I struggled with a half dozen attempts at getting 'a' by itself on the left side, but nothing checked out.
On a hunch, I did a quick google search and found this:
https://www.mathway.com/Algebra[^]
All you do is type in your formula, then it asks which variable you want to solve for. Brilliant!
"Go forth into the source"  Neal Morse





Handy  and quick too!
Can I suggest an extra posting here: Free Tools Discussion Boards[^]  it doesn't get scrolled into oblivion so quickly there.
Sent from my Amstrad PC 1640
Bad command or file name. Bad, bad command! Sit! Stay! Staaaay...
AntiTwitter: @DalekDave is now a follower!





Done!
"Go forth into the source"  Neal Morse





Heck, if it's any more difficult than a + b = c solve for a I'm stuck (I can barely manage the c)!
I never liked math and math dislikes me right back





Very nice, put that away for safe keeping! Thanks
Everyone has a photographic memory; some just don't have film. Steven Wright





Wolfram alpha also does this for you:
http://www.wolframalpha.com/input/?i=solve+x%2F(x%2Bb)+%3D+c%2Fd
Matlab also has similar tools but that costs a lot of money.





Thanks, tried out the wolfram alpha. Too bad they also charge to see the steps.
"Go forth into the source"  Neal Morse





It must be all of the algebra I taught over the years.... burned in my skull.
Now, can you derive the equation of a line given two points?
Muahahaha
Charlie Gilley
<italic>Stuck in a dysfunctional matrix from which I must escape...
"Where liberty dwells, there is my country." B. Franklin, 1783
“They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759





charlieg wrote: Now, can you derive the equation of a line given two points?
Without looking slope = rise/run so m = (y2y1)/(x2x1) (probably not right at all)
Now you're making my brain hurt again! btw, after revisiting my original problem, and thinking a little harder, I was able to work it out.
"Go forth into the source"  Neal Morse





It was rhetorical Slope is correct, but the y intercept?
I worked with a coder who was a wizard in C++. But he had no idea how to code a linear function to calculate a simulated value...
anyway, good math links
Charlie Gilley
<italic>Stuck in a dysfunctional matrix from which I must escape...
"Where liberty dwells, there is my country." B. Franklin, 1783
“They who can give up essential liberty to obtain a little temporary safety deserve neither liberty nor safety.” BF, 1759





Thanks for the link. Bookmarked
M.D.V.
If something has a solution... Why do we have to worry about?. If it has no solution... For what reason do we have to worry about?
Help me to understand what I'm saying, and I'll explain it better to you
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It's trivial https://codeproject.global.ssl.fastly.net/script/Forums/Images/smiley_wink.gif, even after almost 60 years away from Grammar School in England. The steps are, using C formulae:
a / (a + b) = c / d
Multiply both sides by (a + b)
a = (a + b) * c / d
Collect the terms in a
a  a * c / d = b * c / d
Collect the coefficients of a
a * (1  c / d) = b * c / d
Divide both sides by (1  c / d)
a = b * c / d / (1  c / d)
Simplify
a = b * c / (d  c)
Hope that's right, solved before you would have found the program
In those good old days you got the algebra beaten into you
Showoff Jerry





... and c needs to be not equal to d ...





I am so grateful for a post from someone who doesn't feel being innumerate is a way to be part of some team.
Like the slopeofaline question. dy/dx  WTF's the difficulty with high school math?
Something akin to pride as a consequence of membership in a pool of those who "can't" seems to be spreading from the TV and Radio to CP. Maybe the problem with poor code isn't only from the massproduction hordes now being unleashed?
Alas.
Ravings en masse^ 

"The difference between genius and stupidity is that genius has its limits."  Albert Einstein  "If you are searching for perfection in others, then you seek disappointment. If you are seek perfection in yourself, then you will find failure."  Balboos HaGadol Mar 2010 





Probably took me the same amount of time by a slightly different route:
a/(a+b)=c/d
Multiply both sides by (a+b) and by d
ad = c(a+b)
Expand
ad = ac + bc
Subtract ac from both sides
ad  ac = bc
Collect the coefficients of a
a(dc) = bc
Divide both sides by (dc)
a = bc/(dc)
Oh, if only all the equations were linear.





Probably took me the same amount of time by a slightly different route:
You're right, I thought of this after having written the route.
Jerry





I got a slightly different (if not simpler) answer.
a/(a+b) = c/d
a = c/d*(a+b)
a*d/c = a+b
a*d/c a = b
a*(d/c 1) = b
a=b/(d/c1)
Which if you multiply the numerator & denominator by c you'll get the answer the machine reports.





a/(a+b) = c/d
a = c(a+b)/d
a = ca/d + cb/d
a  ca/d = cb/d
ad  ac = cb
a(dc) = cb
a = cb/(dc) A slightly different version from Jerry's. I had 32 credithours of math in college  calculus, differential equations, and matrix algebra. All of it's gone, with the space in my head now used for old movie lines. The algebra's stayed around, as it seems to come in handy now and then.
Software Zen: delete this;



