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C# To average of each group of 20 data
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C#
Hello !

I want to average of each group of 20 data of Barycentre_x Barycentre_y and Barycentre_z. These variables have a number of "cpt" lines (around 600 lines).


I try to do this, but it doesn't run.

C#
Barycentre_x = new double[cpt - 1];
            Barycentre_y = new double[cpt - 1];
            Barycentre_z = new double[cpt - 1];

            for (int i = 0; i < cpt-1; i++) {
                    for (int l = 55; l < 63; l++) {

                            Barycentre_x [i] += nv_data [l].positions [i].x;
                            Barycentre_y [i] += nv_data [l].positions [i].y;
                            Barycentre_z [i] += nv_data [l].positions [i].z;

                    }

                    Barycentre_x [i] /= 8;
                    Barycentre_y [i] /= 8;
                    Barycentre_z [i] /= 8;

            }

// Here I begin the average

Moy_bar_x = new double[Barycentre_x.Length / 20];
Moy_bar_y = new double[Barycentre_y.Length / 20];
Moy_bar_z = new double[Barycentre_z.Length / 20];

while (index_moy + 20 < Barycentre_z.Length) {

                            Moy_bar_x [index_moy % 20] += Barycentre_x [index_moy];
                            Moy_bar_y [index_moy % 20] += Barycentre_y [index_moy];
                            Moy_bar_z [index_moy % 20] += Barycentre_z [index_moy];

index_moy ++;

    if (index_moy % 20 == 0) {

        indice_2++;

                            Moy_bar_x [indice_2] /= 20; 
                            Moy_bar_y [indice_2] /= 20;
                            Moy_bar_z [indice_2] /= 20;
    }
}


At the beginning of the code :

int index_moy = 0;
int indice_2 = -1;
Posted
Updated 14-Jun-15 22:21pm
v6
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3 solutions

Try this;
C#
static void Main(string[] args)
     {
       const int cpt = 153;
       const int taille = 20;
       const double X = 21.5;
       const double Y = -1.98;
       const double Z = 1100.0;
       double [] Barycentre_x = new double [cpt];
       double [] Barycentre_y = new double [cpt];
       double [] Barycentre_z = new double [cpt];

       Random rand = new Random();
       for (int n=0; n < cpt; ++n)
       {
         Barycentre_x[n] = X + (rand.NextDouble()-.5) * Math.Abs(X)/100.0;
         Barycentre_y[n] = Y + (rand.NextDouble()-.5) * Math.Abs(Y)/100.0;
         Barycentre_z[n] = Z + (rand.NextDouble()-.5) * Math.Abs(Z)/100.0;
       }


       const int groupes = cpt / taille;

       double [] Moy_bar_x = new double[groupes];
       double [] Moy_bar_y = new double[groupes];
       double [] Moy_bar_z = new double[groupes];

       int index = 0;
       for (int g = 0; g< groupes; ++g)
       {
         Moy_bar_x[g] = Moy_bar_y[g] = Moy_bar_z[g]= 0.0;
         for (int n=0; n<taille; ++n, ++index)
         {
           Moy_bar_x [g] += Barycentre_x [index];
           Moy_bar_y [g] += Barycentre_y [index];
           Moy_bar_z [g] += Barycentre_z [index];
         }
         Moy_bar_x[g] /= taille;
         Moy_bar_y[g] /= taille;
         Moy_bar_z[g] /= taille;

       }
       for (int g = 0; g < groupes; ++g)
       {
         Console.WriteLine("Moy_bar = ({0},{1},{2})", Moy_bar_x[g], Moy_bar_y[g], Moy_bar_z[g]);
       }
     }
 
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Posted
Updated 14-Jun-15 22:00pm
v2
If you want to do a moving average, then there are two ways you can do it:
1) Keep the last twenty items in an array or similar, and replace the oldest with the latest each time, then re-sum the array.
2) Keep a running total, and when you have twenty items, subtract the value at current-position-twenty from the total, and add the current value.

If you are trying to sum them in groups of twenty, then just use two loops:
Outer loop iterates groups (i.e. moves on in twenties)
Inner loop iterates within a group.

All you need is two indexes (group for output, input) and two counts.
 
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Posted
Comments
Coralie B 15-Jun-15 4:05am    
I update my question.

Is it the good way ?

But I have an error (in comment of my update question)
Coralie B 15-Jun-15 4:32am    
What I do it runs. There are no error message.

But I don't average correctly...
OriginalGriff 15-Jun-15 5:02am    
"run" does not mean "work".
Neither does "no error message"

Seriously, as both CPallini and I have suggested, two loops are a much better option...
Coralie B 15-Jun-15 4:59am    
In my code, I do what I want ?

I calculate the average Moy_bar_ for each group of 20 data which comes from Baycentre_ ?
OriginalGriff 15-Jun-15 5:13am    
Clearly not, if it isn't generating the right values?
C#
int a = -1;
int f = 1;

Moy_bar_x = new double[Barycentre_x.Length / 20];
Moy_bar_y = new double[Barycentre_y.Length / 20];
Moy_bar_z = new double[Barycentre_z.Length / 20];

while (a < (Barycentre_z.Length / 20)-1) {

    a++;
    while ((f % 20) !=0) {

        Moy_bar_x [a] += Barycentre_x[f];
        Moy_bar_y [a] += Barycentre_y[f];
        Moy_bar_z [a] += Barycentre_z[f];

        f++;

    }

    f += 1;

}

for (int b = 0; b < Moy_bar_z.Length; b++) {

    Moy_bar_x[b] /= 20;
    Moy_bar_y[b] /= 20;
    Moy_bar_z[b] /= 20;

}
 
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